asked on

Some help with List and Itterator

In the following method List contains numbers ,

I need to mask those numbers and return them as **-***1234

for (Iterator it = getList().iterator(); it.hasNext();)
{

if (first)
{
buf.append(" | Number(s): ");
first = false;
}
else
{
buf.append(", ");
}

buf.append(it.next().toString());
}

for_yan

StringBuffer buf = new StringBuffer("| Numbers: " ):
for (Iterator it = getEinList().iterator(); it.hasNext();)
{


int ii = it.next();

String s = "" + ii;


if(s.length() >4)buf.append("**-***" + s.substring(s.length()-4 ) + ",");
else buff.append(s);

  }

Open in new window

for_yan

So I guess your list is made up of Integer objects - correct?

Or it is made up if String's which are only digits?

questjava

ASKER

I ithink its strings

for_yan

If its elements are Integer's, then the above code should work,

if its elementas are String;s, then insted of
---
int ii = it.next();

String s = "" + ii;
---
you should just use:
---
String s = it.next();
---

for_yan

then this should work:

StringBuffer buf = new StringBuffer("| Numbers: " ):
for (Iterator it = getEinList().iterator(); it.hasNext();)
{




String s = it.next();


if(s.length() >4)buf.append("**-***" + s.substring(s.length()-4 ) + ",");
else buff.append(s);

  }

Open in new window

questjava

ASKER

int ii =it.next();

or string ii =it.next();

error type mismatch .. cannot convet from object to string/int

ASKER CERTIFIED SOLUTION

for_yan

membership

This solution is only available to members.

To access this solution, you must be a member of Experts Exchange.

Start Free Trial

for_yan

it should be
String s = (String) it.next();