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  • Status: Solved
  • Priority: Medium
  • Security: Public
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Query

Hi,

I have quer in sql and I want to convert it in MS access

update  YourTable
  Set   ColumnResult  =case when SUBSTRING(RIGHT(column1,7),1,2)='ws' then 'JK'
              when SUBSTRING(RIGHT(column1,7),1,2)='sa' then 'KR'
         end        
0
samprg
Asked:
samprg
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2 Solutions
 
als315Commented:
IIF(mid(Right(column1,7),1,2)="ws", "JK", IIF(mid(Right(column1,7),1,2)="sa","KR",""))
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als315Commented:
Of full query (for Table1):
UPDATE Table1 SET Table1.ColumnResult = IIf(Mid(Right([column1],7),1,2)="ws","JK",IIf(Mid(Right([column1],7),1,2)="sa","KR",""));
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als315Commented:
For YourTable:
UPDATE YourTable SET YourTable.ColumnResult = IIf(Mid(Right([column1],7),1,2)="ws","JK",IIf(Mid(Right([column1],7),1,2)="sa","KR",""));
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pdebaetsCommented:
update  YourTable Set   ColumnResult  = iif(Instr(1,RIGHT(column1,7),2)='ws,'JK',iif(Instr(1,RIGHT(column1,7),2)='sa','KR',""))
Where Instr(1,RIGHT(column1,7),2)='ws OR Instr(1,RIGHT(column1,7),2)='sa';
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samprgAuthor Commented:
How can I use
IIF(mid(Right(column1,7),1,2)="ws", "JK", IIF(mid(Right(column1,7),1,2)="sa","KR",""))
in  update statement
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samprgAuthor Commented:
I am sorry, I did not see your answers I should refresh IE.
I will try it
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pdebaetsCommented:
My use of "Instr" is incorrect above. Please use

update  YourTable Set   ColumnResult  = iif(Mid(RIGHT(column1,7),1,2)='ws,'JK',iif(Mid(RIGHT(column1,7),1,2)='sa','KR',""))
Where Mid(RIGHT(column1,7),1,2)='ws OR Mid(RIGHT(column1,7),1,2)='sa';
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samprgAuthor Commented:
Awesome
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