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java function

I saw a java code snippet which was something similiar to this

Fetch.func1().func2()

I understand that Fetch is a class and func1 is method in that class, but i am not sure what is func2 is it also a method in class fetch ? and also want to when can i use this type of function call...please help

~manu

 
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manugeek
Asked:
manugeek
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3 Solutions
 
a_bCommented:
Fetch.func1().func2() => Fetch is a class that has a method func1().

Fetch.func1() returns an object that has the method func2(), therefore you can invoke func2().
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a_bCommented:
Eg -

Class A
{
    public B func()1
   {
        .......
   }
}

Class B
{
   public void func()2
   {
        .......
   }  
}

You can try writting a test harness for these classes.
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for_yanCommented:
Well there is no gurantee in this notation, but one may assume that Fetch is a class, func1() is a static methid of this class which returns an instance of another class, and then method func2() is invojed on the instance of the result of funnc1()
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for_yanCommented:
We can make conclusion that Fetch is a class and func1() is a static method because first letter of Fetch is capitalized and the convention is that class names are written starting with capital leeter
Howerver convention is not a law, so we cannot exclude that Fetch is an instance of some class. If so, then func1() would be an instance method - we should see more code to know for sure
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Hugh McCurdyCommented:
I thought it might help to give an example from a program.  This example is from a simple interactive fiction ("adventure") game.

Path path = player.getRoom().getPath( direction );

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Here the player is trying to leave the room he's currently in.  player is an object for the player.  getRoom() is a method in Player that returns the room the player currently occupies.  getPath() is a method in Room that accepts a compass direction and returns a path object (which may be null, meaning the direction is invalid).

The method continues.  I'm showing it just to give you some context.

If the path isn't null, we use a method in Path to get the room at the end of the path.  (The path can be very short, ie a door or doorway).

We have more "chained" messages (function calls).  I will explain what those do if you indicate it will help.  Better would be, if you can, explain to me what you think they do and get me (or someone) to review your answer.  (My assumption is you want to learn.)

        if ( path == null )
        {
            myScreen.setDescription ( "You can't go that way." );
        }
        else
        {
            Room nextRoom = path.getRoom();
            
            if ( player.getRoom().getPath ( direction ).getLocked())
            {
                myScreen.setDescription ( player.getRoom().getPath ( direction ).getWhyLocked() );
            }
            else // unlocked
            {
                if ( player.setRoom ( nextRoom ))
                myScreen.setDescription ( player.getRoom() );
            } // else
                
        } // else

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manugeekAuthor Commented:
Thank @hmccurdy: for the detailed explanation. Now this makes sense to me :-)

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manugeekAuthor Commented:
Thanks all for the answers...
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Hugh McCurdyCommented:
Thanks.  Never mind for the program bug that remained (oops) after I removed some lines of code that would be confusing.

I'm glad it makes sense to you now.  Gets my day off to a good start.
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