Solved

How to I fix query to get rid of error ORA-00923: FROM keyword not found where expected

Posted on 2011-09-23
6
498 Views
Last Modified: 2012-05-12
when I execute the following query:

Select count to_char(publication_date, 'DD-MON-YYYY') as count, publication_date from bib_holdings group by publication_date order by publication_date;

                    *
ERROR at line 1:
ORA-00923: FROM keyword not found where expected


What is wrong with this query?
0
Comment
Question by:sikyala
  • 3
  • 2
6 Comments
 
LVL 76

Accepted Solution

by:
slightwv (䄆 Netminder) earned 250 total points
ID: 36588188
Count is a function

Select count(1), to_char(publication_date, 'DD-MON-YYYY') a from...
0
 
LVL 73

Expert Comment

by:sdstuber
ID: 36588214
there is no need to convert the date if you're going to count it, just count the date as is

Select count(publication_date) as count, publication_date from bib_holdings group by publication_date order by publication_date;

or

Select count(*) as count, publication_date from bib_holdings group by publication_date order by publication_date;

0
 
LVL 73

Expert Comment

by:sdstuber
ID: 36588223
note  count(*) and count(1) are equivalent,  count(*) is recommended practice by oracle

internally it will rewrite it as count(*) anyway


the difference between count(*) and count(publication_date)  is the handling of NULL values.

count(*) will count rows, regardless of whether they have nulls or not

count(publication_date) will count NOT-NULL values only

count(to_char(publication_date,'DD-MON-YYYY'))  will also count NOT_NULL values only, so the extra conversion isn't necessary
0
PRTG Network Monitor: Intuitive Network Monitoring

Network Monitoring is essential to ensure that computer systems and network devices are running. Use PRTG to monitor LANs, servers, websites, applications and devices, bandwidth, virtual environments, remote systems, IoT, and many more. PRTG is easy to set up & use.

 
LVL 76

Expert Comment

by:slightwv (䄆 Netminder)
ID: 36588277
I assumed they wanted to count the days not the time portion which is why I moved the to_char outside the count.
0
 
LVL 73

Assisted Solution

by:sdstuber
sdstuber earned 250 total points
ID: 36588327
ah, that changes the group by then too
and makes the order by tricky since the the dates will be strings

Select count(*) as count, to_char(publication_date,'dd-MON-yyyy') publication_date from bib_holdings group by to_char(publication_date,'dd-MON-yyyy')
order by to_char(publication_date,'dd-MON-yyyy')   -- this probably the wrong order by

alternately  use trunc to count by day

Select count(*) as count, trunc(publication_date) publication_date
from bib_holdings
group by trunc(publication_date)
order by trunc(publication_date)
0
 

Author Closing Comment

by:sikyala
ID: 36588352
Thanks it worked
0

Featured Post

Is Your Active Directory as Secure as You Think?

More than 75% of all records are compromised because of the loss or theft of a privileged credential. Experts have been exploring Active Directory infrastructure to identify key threats and establish best practices for keeping data safe. Attend this month’s webinar to learn more.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Background In several of the companies I have worked for, I noticed that corporate reporting is off loaded from the production database and done mainly on a clone database which needs to be kept up to date daily by various means, be it a logical…
How to Unravel a Tricky Query Introduction If you browse through the Oracle zones or any of the other database-related zones you'll come across some complicated solutions and sometimes you'll just have to wonder how anyone came up with them.  …
This video shows how to copy a database user from one database to another user DBMS_METADATA.  It also shows how to copy a user's permissions and discusses password hash differences between Oracle 10g and 11g.
This video shows setup options and the basic steps and syntax for duplicating (cloning) a database from one instance to another. Examples are given for duplicating to the same machine and to different machines

895 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question

Need Help in Real-Time?

Connect with top rated Experts

15 Experts available now in Live!

Get 1:1 Help Now