Solved

cannot divide by zero c++

Posted on 2011-09-23
6
349 Views
Last Modified: 2012-05-12
Hello i'm trying to get my program to work correctly.. the program is very simple all it does is caculate various basic math operations.. i have posted what it is suppose to do
Please enter two integer values separated by whitespace: 5 2
Here are the results:
5 plus 2 equals 7
5 minus 2 equals 3
5 multiplied by 2 equals 10
5 divided by 2 equals 2 with a remainder of 1
But with the second operand having a value of zero, we should see the following:

Please enter two integer values separated by whitespace: 5 0
Here are the results:
5 plus 0 equals 5
5 minus 0 equals 5
5 multiplied by 0 equals 0
Division by zero is undefined...

although my code something is wrong and still passing the zero to the function even though it's suppose to say "Division by zero is undefined..."  i have posted my code below..

#include <iostream>
using namespace std;
void CalcIntResults(int value1, int value2,  int &addition_total, int &minus_total, int &mulplication, int &division, int &reminder);

int main(void)
{
	int number1;
	int number2;

	int addition;
	int minus;
	int mulplication;
	int division;
	int reminder;

cout <<"Please enter two integer values seperated by whitespace: ";
cin >> number1 >>number2;
CalcIntResults(number1, number2, addition, minus, mulplication, division, reminder);

cout <<number1 <<" plus " <<number2 <<" equals " <<addition <<endl;
cout <<number1 <<" minus "<<number2 <<" equal " <<minus <<endl;
cout <<number1 <<" multiplied " <<number2 <<" equals " <<mulplication <<endl;

if(number2!=0)
{
cout <<number1 <<" divided " <<number2 <<" equals " <<division;
}

else 

{
	cout <<"Division by zero is undefined";
}


if((number1 % number2)!=0)
{
	cout <<" reminder of " << reminder;

}
else 
{
	cout <<" no reminder";
}


}
void CalcIntResults(int value1, int value2, int &addition_total, int &minus_total, int &mulplication, int &division, int &reminder)
{
	addition_total = value1+value2;
	minus_total= value1-value2;
	mulplication= value1*value2;

	if(value2 !=0)
	{
		division = value1/value2;
	}
	else
	{
		cout <<"Division by zero is undefined";
	}
	

}

Open in new window

0
Comment
Question by:businessesatoz
  • 5
6 Comments
 
LVL 13

Expert Comment

by:themrrobert
ID: 36589008
try changing line 24 to this:

if(number2!='0')
0
 
LVL 13

Expert Comment

by:themrrobert
ID: 36589018
if that doesnt work (which it probably will) try this:

if(number2!="0")

the operators in c++ are extermely sensitive, and a char or string (as returned from stding) will not be cast to an int unless explicitly specified. another thing to try is

if(int<number2>!=0)

/\ this is probably best solution
0
 
LVL 13

Expert Comment

by:themrrobert
ID: 36589029
I see that you are casting it to an int, i'm going to pull out my compiler and check it out

(try my solution just for fun, it may work :) )
0
Is Your Active Directory as Secure as You Think?

More than 75% of all records are compromised because of the loss or theft of a privileged credential. Experts have been exploring Active Directory infrastructure to identify key threats and establish best practices for keeping data safe. Attend this month’s webinar to learn more.

 
LVL 13

Accepted Solution

by:
themrrobert earned 500 total points
ID: 36589049
I found the problem: use this code


Problem solved B)
if(number2!=0)
{
cout <<number1 <<" divided " <<number2 <<" equals " <<division;
if((number1 % number2)!=0)
{
	cout <<" reminder of " << reminder;

}
else 
{
	cout <<" no reminder";
}
}

else 

{
	cout <<"Division by zero is undefined";
}

Open in new window

0
 
LVL 13

Expert Comment

by:themrrobert
ID: 36589074
Complete code, just to make it easier: (sorry for spamming, my brain is on overload right now )
#include <iostream>
using namespace std;
void CalcIntResults(int value1, int value2,  int &addition_total, int &minus_total, int &mulplication, int &division, int &reminder);

int main(void)
{
	int number1;
	int number2;

	int addition;
	int minus;
	int mulplication;
	int division;
	int reminder;

cout <<"Please enter two integer values seperated by whitespace: ";
cin >> number1 >>number2;
CalcIntResults(number1, number2, addition, minus, mulplication, division, reminder);

cout <<number1 <<" plus " <<number2 <<" equals " <<addition <<endl;
cout <<number1 <<" minus "<<number2 <<" equal " <<minus <<endl;
cout <<number1 <<" multiplied " <<number2 <<" equals " <<mulplication <<endl;

if(number2!=0)
{
	cout <<number1 <<" divided " <<number2 <<" equals " <<division;
	if((number1 % number2)!=0)
	{
		cout <<" reminder of " << reminder;

	}
	else 
	{
		cout <<" no reminder";
	}
}

else 

{
	cout <<"Division by zero is undefined";
}


}
void CalcIntResults(int value1, int value2, int &addition_total, int &minus_total, int &mulplication, int &division, int &reminder)
{
	addition_total = value1+value2;
	minus_total= value1-value2;
	mulplication= value1*value2;

	if(value2 !=0)
	{
		division = value1/value2;
	}
	else
	{
		cout <<"Division by zero is undefined";
	}
	

}

Open in new window

0
 

Author Closing Comment

by:businessesatoz
ID: 36589105
thanks i was very close this one was a bit tricky... thanks !!!!
0

Featured Post

Is Your Active Directory as Secure as You Think?

More than 75% of all records are compromised because of the loss or theft of a privileged credential. Experts have been exploring Active Directory infrastructure to identify key threats and establish best practices for keeping data safe. Attend this month’s webinar to learn more.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Suggested Solutions

Introduction This article is a continuation of the C/C++ Visual Studio Express debugger series. Part 1 provided a quick start guide in using the debugger. Part 2 focused on additional topics in breakpoints. As your assignments become a little more …
Basic understanding on "OO- Object Orientation" is needed for designing a logical solution to solve a problem. Basic OOAD is a prerequisite for a coder to ensure that they follow the basic design of OO. This would help developers to understand the b…
The viewer will learn how to use the return statement in functions in C++. The video will also teach the user how to pass data to a function and have the function return data back for further processing.
The viewer will be introduced to the technique of using vectors in C++. The video will cover how to define a vector, store values in the vector and retrieve data from the values stored in the vector.

914 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question

Need Help in Real-Time?

Connect with top rated Experts

15 Experts available now in Live!

Get 1:1 Help Now