Solved

JavaScript Date functions

Posted on 2011-09-23
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Last Modified: 2012-05-12
This works OK, but not if the two dates are the same:

      // check tdate today or ahead
            fdt = new Date(document.rev.tdate.value);
            dnow = new Date();
            if (fdt.getTime() < dnow.getTime()) {
                  alert("Flight date before today.");
                  return false;
            }      

The format of document.rev.tdate is mm/dd/yy.

Why doesn't this work?            
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Question by:Richard Korts
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4 Comments
 
LVL 82

Expert Comment

by:leakim971
ID: 36588981
replace :  
fdt = new Date(document.rev.tdate.value);

Open in new window

by :  
afdt = document.rev.tdate.value.split("/");
fdt = new Date(2000 + afdt[2], parseInt(afdt[0])-1, afdt[1]); // january = 0, decembre = 11

Open in new window


a good article : http://www.experts-exchange.com/Programming/Languages/Scripting/JavaScript/A_484-Can-I-have-a-date.html
don't forget to vote ;-)
0
 
LVL 41

Expert Comment

by:HonorGod
ID: 36589041
@leakim971 I'm glad that you find my article useful.  Thanks for sharing the link!
0
 

Author Comment

by:Richard Korts
ID: 36589131
To leakim971:

Doesn't work. I found out the format was really mm/dd/yyyy, so I changed it to this:

            afdt = document.rev.tdate.value.split("/");
            fdt = new Date(afdt[2], parseInt(afdt[0])-1, afdt[1]); // january = 0, decembre = 11

Still fails for today.
0
 
LVL 82

Accepted Solution

by:
leakim971 earned 500 total points
ID: 36589245
>@leakim971 I'm glad that you find my article useful.  Thanks for sharing the link!
My pleasure!


>Still fails for today.
Add hour, min and second : fdt = new Date(afdt[2], afdt[0]*1-1, afdt[1],23,59,59); // january = 0, decembre = 11
test page : http://jsfiddle.net/5wuRR/
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