Link to home
Start Free TrialLog in
Avatar of kenuk110
kenuk110

asked on

Create D/B records that are entered from files saved in directories

Hi,

I have files which are delivered through DropBox to my file server, what I'd like to do it when a file is 'dropped', something scans the directories, finds the latest saved file, enters a record in the DB which points to this file.

Is this possible? The naming convention of all the files is the same so the format won't change, the directory it resides in though is the differentiator.

So, the filename is like this:

IMG00001-201109024-1441.jpg

the length of each part won't change, so the first part IMG00001 will always be IMG003432 for example, the format will never change.

The directories are similar:

\\photos\02\006-S\AA12

the second and third part of the structure will never change from a 2 digit/5 digit structure, the last part could be 2-4 alphanumerics.

I know this is probably impossible but thought I'd ask the question anyway!!

Any help would be much appreciated.

Regards,

Ken



Avatar of nrbreen
nrbreen

Very little is impossible,
what approx number of folders and files need to be catered for?
ASKER CERTIFIED SOLUTION
Avatar of nrbreen
nrbreen

Link to home
membership
This solution is only available to members.
To access this solution, you must be a member of Experts Exchange.
Start Free Trial
Avatar of kenuk110

ASKER

Thank you nrbreen!

Let me try this on my system, I really appreciate it, I'm not a programmer and haven't also used VB, the limited stuff I have done has been on C Sharp but let me change the parts you have suggested.

Really appreciate it.

Cheers,

Ken
Hi nrbreen,

Right, I have gone through the file, it all came in in one long string so I had to press enter a load of times, hence taking a little time to get back to you!

It all seems to be trying to do what it should but I have an issue where it requires the username and password for our SQL Server. Is there a way to add this information to the connection string as the message I get back is:

Login failed for user''.

Any ideas?
Hi again,

It works!!! I found the additional info on the net so added it and it works like a dream!

I really appreciate your help on this.

Best Regards,

Ken