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A survey of the cost of one-pound bags of potato chips at five local supermarkets is shown in the attached stem-and-leaf plot. How many bags of chips cost less than the median price of a bag of chips?

Key of stem-and_leaf plot is as follows:

15 | 9 means $1.59

Our solution: $1.59, $1.69, $1.75, $1.79, $1.88, $1.89, $1.99, $1.99, $1.99, $1.99, $1.99, $2.09, $2.15, $2.15, $2.18, $2.19, $2.25, $2.29, $2.29, $2.39, $2.40, $2.59

Median = ($1.99 + $2.09)/2 = $2.04

but our answer doesn't come out to be 6.

Key of stem-and_leaf plot is as follows:

15 | 9 means $1.59

Our solution: $1.59, $1.69, $1.75, $1.79, $1.88, $1.89, $1.99, $1.99, $1.99, $1.99, $1.99, $2.09, $2.15, $2.15, $2.18, $2.19, $2.25, $2.29, $2.29, $2.39, $2.40, $2.59

Median = ($1.99 + $2.09)/2 = $2.04

but our answer doesn't come out to be 6.

BUT

you have a leaf diagram and the middle of it is 6 items above the bottom. (The real middle is at 5.5 as per your calculation but that rounds to 6

Please see this article on HOW to find the "**median value**".

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24 has no leaves... Empty stem, with no data. If it were meant to be 2.40 you would see 24|0

>Since $1.99 is one of two median numbers, should it be counted as one of 6 prices? If it's counted, then there are 7 prices less than median price.

When there are an even number of points you take the mean of the two middle points as you showed in the text of the question and derive a single median. However there is an odd number of points (21), so 1.99 is the median number we need to consider.

The question "How many bags of chips cost less than the median price of a bag of chips?" indicates not the number of points before the median, but the number of data points that are less than the median. There are exactly six ($1.59, $1.69, $1.75, $1.79, $1.88, $1.89)