Solved

MSAccss, Oracle Connection, Password Form

Posted on 2011-09-25
3
204 Views
Last Modified: 2012-05-12
I thought I had this worked out with an earlier question, but I still don't have a working process.

I am trying to build a process where a connection to an oracle db is built up to the point where the password is needed. At that point, I want a password form to open and ask for the password (I already have the userID), and when the user enters the password and clicks the "Enter" button, the password gets passed back to the function that is building the oracle connection (strACSConnectionACS()), and it sends the connection over to the db for authentication and connection.

When I run it, the password form opens, but the code doesn't stop and wait for the user to enter the password.  It tries to connect without the password and I get an error message.  
Also, I can't figure out how to get the form closed after the user enters their password.  

I've attached my code.  If you see what I've got wrong please spell it out for me in detail - I can't seem to get the drift of how this is suppose to work.

Thanks, Lynn ACS.txt
0
Comment
Question by:Lambel
  • 2
3 Comments
 
LVL 61

Expert Comment

by:mbizup
ID: 36596798
If you simply need the code to pause until the dialog box closes, change your code to this:

Function strGetACSPswdd() As STring
      DoCmd.OpenForm "frmEnterACSPswd",,,,,acDialog
End Function


You may also need to add a special case to handle null/blank input so that it is not tagged onto your connection string.
0
 
LVL 61

Accepted Solution

by:
mbizup earned 500 total points
ID: 36596809
That said, you could also use a simple input box to handle everything (without the popup form):

Function strACSConnectionACS() As String
              Dim strPWD as string
              strPWD = "" & inputbox("Enter a password:")

               if strPWD = "" then
                     msgbox "No Password entered"
                     exit function
               end if

      strACSConnectionACS = "more lines of connection information"
      strACSConnectionACS = strACSConnectionACS & "Password=" & strPWD & ";"
End Function
0
 

Author Closing Comment

by:Lambel
ID: 36600410
Thanks, I used this along with some features I found to tweek the inputbox so that it hides the input characters.  I think I finally have a working process.

Greatly appreciated!
Lynn
0

Featured Post

Free Tool: Site Down Detector

Helpful to verify reports of your own downtime, or to double check a downed website you are trying to access.

One of a set of tools we are providing to everyone as a way of saying thank you for being a part of the community.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

When you are entering numbers in a speadsheet, and don't remember what 6×7 is, you just type “=6*7" instead. It works in every cell! This is not so in Access. To enter the elusive 42 in a text box, you have to find a calculator, and then copy the re…
It’s the first day of March, the weather is starting to warm up and the excitement of the upcoming St. Patrick’s Day holiday can be felt throughout the world.
In Microsoft Access, learn different ways of passing a string value within a string argument. Also learn what a “Type Mis-match” error is about.
In Microsoft Access, learn the trick to repeating sub-report headings at the top of each page. The problem with sub-reports and headings: Add a dummy group to the sub report using the expression =1: Set the “Repeat Section” property of the dummy…

820 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question