create an infinite loop in jquery

setTimeout is a function that will never stop unless you call clearTimeout

http://www.w3schools.com/js/js_timing.asp

<script type="text/javascript">
  var aImages = new Array();
  var imageNum = 1;
  aImages[0] = "img/limerick.jpg";
  aImages[1] = "img/launch.jpg";
  aImages[2] = "img/graduates.jpg";
  aImages[3] = "img/portrait.jpg";
  aImages[4] = "img/wedding.jpg";
  aImages[5] = "img/engagement.jpg";
  aImages[6] = "img/wedding2.jpg";
  $(document).ready(function() {
    while (imageNum < 7) {
     
      $("img#bg").attr("src", aImages[imageNum]);
      $("img#bg").load
      $("img#bg").fadeIn(1000);
      setTimeout(function() {$("img#bg").fadeOut(1000);},3000);
      imageNum ++;
      }
      });
</script>

<script type="text/javascript">
  var aImages = new Array();
  var imageNum = 1;
  aImages[0] = "img/limerick.jpg";
  aImages[1] = "img/launch.jpg";
  aImages[2] = "img/graduates.jpg";
  aImages[3] = "img/portrait.jpg";
  aImages[4] = "img/wedding.jpg";
  aImages[5] = "img/engagement.jpg";
  aImages[6] = "img/wedding2.jpg";
  $(document).ready(function() {
       setTimeout(changeimg,3000)

      });
function changeimg(){
      var img = $("img#bg");
      img.fadeOut(1000);
      if(++imageNum==7)imageNum=0;
      img.attr("src", aImages[imageNum]).load().fadeIn(1000);
}
</script>

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eyal thanks your for your code but it does not appear to loop.  it displays the first image then stops.

Problem lies in line 12 to 15.
Exit condition of the loop is imageNum = 10, but when it is 7, you reset it --> the loop will never end.
Use either suggestion of Pratima or Eyal is fine :)

i want to keep the infinite loop.  the exit condition is never expected to be met.  the problem is the browser becomes no responsive.

callMeAgainLater();
function callMeAgainLater()
{
   ...your code here...
   setTimeout( "callMeAgainLater()", 1000 );
}

above code will keep on looping

<script type="text/javascript">
  var aImages = new Array();
  var imageNum = 1;
  aImages[0] = "img/limerick.jpg";
  aImages[1] = "img/launch.jpg";
  aImages[2] = "img/graduates.jpg";
  aImages[3] = "img/portrait.jpg";
  aImages[4] = "img/wedding.jpg";
  aImages[5] = "img/engagement.jpg";
  aImages[6] = "img/wedding2.jpg";
  $(document).ready(function() {
       setTimeout(changeimg,3000)

      });
function changeimg(){
      var img = $("img#bg");
      img.fadeOut(1000);
      if(++imageNum==7)imageNum=0;
      img.attr("src", aImages[imageNum]).load().fadeIn(1000);
      setTimeout(changeimg,3000)
}
</script>

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Eyal that code works but strange things are happening with the pictures.  A picture appears, fades out, then fades in again.  The next picture appears, fades out and fades in again.

It does loop correctly though.