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possible to read img properties and assign variable to the title?

Posted on 2011-09-26
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Last Modified: 2012-05-12
I was wondering if it is possible to read IMG properties and assign the title to a variable that I can use. I am not sure where to start with this. I went to php.net and found this exif_read_data() but couldn't determine if that is what I should be using for this.
any help would be great even a link to the right php function I should be trying to use.
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Question by:jaxbrian
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7 Comments
 
LVL 6

Expert Comment

by:neorush
ID: 36600740
Are you trying to read the properties of an <img /> tag?  e.g. <img src="myimage.jpg" title="test"> or are you trying to read the properties of an image file?  e.g. http://www.example.com/myimage.jpg?  What information are you trying to get?
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Author Comment

by:jaxbrian
ID: 36600772
sorry I wasn't clear on that. I am trying to read the title in the img properties itself  /folder/picture.jpg

I am using a readdir now to get all the images from a folder but I want to get the title of each image as well so can echo them into the <img src="folder/picture.jpg" title="<php echo $title; ?>">


thanks
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LVL 6

Expert Comment

by:neorush
ID: 36600914
Some tags are / are not available depending on the image and how it was saved.  e.g. photoshops "save for web and devices" strips most exif data.  But here is how you would access that information.  Your server would also have to have php's exif extensions installed.
<?php
function getExifTitle($image){
	echo "Examing ".$image."<br />\n";
	$exif = exif_read_data($image, 'IFD0');
	if($exif===false){
		echo "No header data found.<br />\n";
		return false;
	}
	else echo "Image contains headers<br />\n";

	$exif = exif_read_data($image, 0, true);
	foreach ($exif as $key => $section) {
		foreach ($section as $name => $val) {
			echo "$key.$name: $val<br />\n";
		}
	}
	return $exif;
}
$exif_data = getExifTitle('folder/picture.jpg');
?>

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LVL 2

Author Comment

by:jaxbrian
ID: 36601025
so I filled out all the information in the properties to see what it would retrieve. I would like to be able to set this which is one of the returned values "IFD0.ImageDescription: TEST to see"
to a variable, but I only want the value and in this case it would be "TEST to see"

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LVL 6

Expert Comment

by:neorush
ID: 36601081
if the field ImageDescription is not present in the image, you will get no output.  Other wise you will get the contents of the field.  
<?php
function getExifTitle($image){
	$exif = exif_read_data($image, 'IFD0');
	if($exif) $exif = exif_read_data($image, 0, true);
	if(isset($exif['IFD0']['ImageDescription'])) return $exif['IFD0']['ImageDescription'];
	else return false;
}
echo getExifTitle('picture.jpg');
?>

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Accepted Solution

by:
neorush earned 500 total points
ID: 36601094
Sorry, missed a return so there are no possible errors.
<?php
function getExifTitle($image){
	$exif = exif_read_data($image, 'IFD0');
	if($exif) $exif = exif_read_data($image, 0, true);
	else return false;
	if(isset($exif['IFD0']['ImageDescription'])) return $exif['IFD0']['ImageDescription'];
	else return false;
}
echo getExifTitle('picture.jpg');
?>

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LVL 2

Author Closing Comment

by:jaxbrian
ID: 36602599
thank you very much. i am going to read more about the exif_read_data()
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