A Geometry question.
Posted on 2011-09-26
Visualize a 50 foot pole that is perpendicular to the ground.
The pole breaks, 17 feet from the ground. The 33 foot top section, begins it's fall in the due west direction. There is no wind or other external force, other than gravity.
The top 33 feet begins it's arc downward, and it's arcing motion creates part of a semi-circle, with a radius of 33 feet (the length of the section of pole).
An obstruction is resting on the ground, and it is 36 feet from the base of the pole, and sitting outside the radius of the 33 foot arc.
If the obstruction was to be raised off the ground, completely perpendicular to the ground level, how many feet would it have to be raised for the obstruction to touch the outside edge of the 33 foot arc?