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Oracle SQL Syntax for Aggregate Cp

Posted on 2011-09-27
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Last Modified: 2012-05-12
select distinct dictatorid,dictatorlastname, count(dictatorid) 
from ichart.transactions where
reportperiod = '201108'
group by dictatorid, dictatorlastname
order by dictatorid ASC;

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Can someone tell me how to modify this Oracle query so it only returns records where the total of each distinct dictatorid is greater than 1?   I am trying to identify dictatorid's that have been assigned to more than one last name and what last names they are assigned to.

Thanks!
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Question by:codefinger
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9 Comments
 
LVL 74

Expert Comment

by:sdstuber
ID: 36711831
SELECT   dictatorid, dictatorlastname
    FROM (SELECT dictatorid, dictatorlastname, COUNT(*) OVER (PARTITION BY dictatorid) cnt
            FROM ichart.transactions
           WHERE reportperiod = '201108')
   WHERE cnt > 1
ORDER BY dictatorid ASC;
0
 
LVL 77

Expert Comment

by:slightwv (䄆 Netminder)
ID: 36711835
Something like:

select dictatorid,dictatorlastname, count(dictatorid)
from ichart.transactions where
   reportperiod = '201108'
group by dictatorid, dictatorlastname
having count(dictatorid) > 1
order by dictatorid ASC;
0
 
LVL 77

Expert Comment

by:slightwv (䄆 Netminder)
ID: 36711842
sorry.   I missed the different last name piece.
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Author Comment

by:codefinger
ID: 36712127
None of these answers is quite doing it for me.

The way I see it, if any dictatorid shows up at all it should show up at least twice,
ex:  1800NOC     SMITH        2
       1800NOC     JONES       2

But with the examples so far I am getting dictatorids that show up only once with only one of the last names that are assigned to it.

Please try again!

Thanks!
0
 
LVL 74

Expert Comment

by:sdstuber
ID: 36712149
I made the assumption that a given dictator/name combo was unique.

my original query should have picked up what you have shown
but could have also given false-postives on

1, codefinger
1, codefinger

as that is a count of 2 for that id,

this will handle duplicate names on a single id  and will ignore the above


SELECT   dictatorid, dictatorlastname
    FROM (SELECT dictatorid,
                 dictatorlastname,
                 COUNT(DISTINCT dictatorlastname) OVER (PARTITION BY dictatorid) cnt
            FROM transactions
           WHERE reportperiod = '201108')
   WHERE cnt > 1
ORDER BY dictatorid ASC;
0
 
LVL 74

Expert Comment

by:sdstuber
ID: 36712156
if this doesn't work,  please provide some sample data that fails,  along with expected results
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Author Comment

by:codefinger
ID: 36712227
sdstuber,

That seems to work pretty well when I add DISTINCT to the first line.  I can probably get away with that, but it would be really cool if I could also have a column that counted the distinct instances so I could sort by it.....so the most over-used dictatorid's could be at the top....

Care to give it a try?
0
 
LVL 74

Accepted Solution

by:
sdstuber earned 500 total points
ID: 36712360
SELECT   dictatorid, dictatorlastname, cnt
...

order by cnt desc
0
 

Author Closing Comment

by:codefinger
ID: 36712638
THANK YOU!
0

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