Modern healthcare requires a modern cloud. View this brief video to understand how the Concerto Cloud for Healthcare can help your organization.
Solved
how to sumbit a form in a jquery without loading the result?
Posted on 2011-09-27
Hi All Im trying to submit a form using jquery
and to send the form into a php page that will update the db without sending any result back to the element (I guess using ajax)
fElement.submit(function(e
//fElement.attr('flag','1'
e.preventDefault();
//"mark" the input name =flag as spam
$(":hidden[name='flag']","
fElement.toggle();
//hoe to post/get the form $.ajax(
and to send the form into a php page that will update the db without sending any result back to the element (I guess using ajax)
fElement.submit(function(e
//fElement.attr('flag','1'
e.preventDefault();
//"mark" the input name =flag as spam
$(":hidden[name='flag']","
fElement.toggle();
//hoe to post/get the form $.ajax(
<form id = "popup_form_{$row['id']}" action ="" method ="post" style="background-color:white; border:2px solid blue;padding:4px; width:250px; display :none; position:absolute" onsubmit = "return false;">
<input type ="hidden" name="flag" value = "no" >
<input type="hidden" name="id" value ="{$row['id']}">
<input type="hidden" name ="email" value ="{$row['email_address']}">
<input type="submit" value="SpamIt" name="spamIt" style="margin-right:15px;">
<input type="button" value="Close" onclick="closePopup()"/>
</form>
</tr>
[X]
Welcome to Experts Exchange
Add your voice to the tech community where 5M+ people just like you are talking about what matters.
- Help others & share knowledge
- Earn cash & points
- Learn & ask questions
-
5
2
8 Comments
There are numerous ways you can achieve this goal of submitting a form, changing to a new page without returning data back to an element.
It looks like you'd prefer not to use a serverside PHP solution, and to have it completely run via javascript and ajax.
jQuery Ajax documentation is the page for structuring the name value pairs, and to achieve the method of operation you desire. You'll probably want to trigger this ajax event with an event handler that applies a javascript controlled submit.
The raw bones of the code ends up something like:
It looks like you'd prefer not to use a serverside PHP solution, and to have it completely run via javascript and ajax.
jQuery Ajax documentation is the page for structuring the name value pairs, and to achieve the method of operation you desire. You'll probably want to trigger this ajax event with an event handler that applies a javascript controlled submit.
The raw bones of the code ends up something like:
$('#myForm').submit(function() {
$.ajax({
url: 'myphpsubmitpage.php',
success: function( ) {
//do nothing
},
complete: function() {
// replace form with another element code, else code to redirect to another page as desired
}
});
});
Greg's answer covers it mostly, but isn't clear in describing how you'd prefer to "not to use a serverside PHP solution".
You'll still need PHP, since javascript cannot interact with the DB. Using jquery's ajax method is the proper solution. jQuery also provides a nice function for serializing a form into a data structure you cvan submit via jQuery's ajax. http://api.jquery.com/serialize/
So you can do something like:
Alternatively, there are nice jquery plugins that do most of this already. Check out http://www.jainaewen.com/files/javascript/jquery/iframe-post-form.html or http://jquery.malsup.com/form/
-Matt
You'll still need PHP, since javascript cannot interact with the DB. Using jquery's ajax method is the proper solution. jQuery also provides a nice function for serializing a form into a data structure you cvan submit via jQuery's ajax. http://api.jquery.com/serialize/
So you can do something like:
$('#myForm').submit(function(){
$.ajax({
data: $(this).serialize(),
url: 'formSubmit.php'
});
Alternatively, there are nice jquery plugins that do most of this already. Check out http://www.jainaewen.com/files/javascript/jquery/iframe-post-form.html or http://jquery.malsup.com/form/
-Matt
"and to send the form into a php page that will update the db"
I was talking about it being a standard javascript handler into a standard PHP receipt page (alas - url: 'myphpsubmitpage.php') that only takes name||value pairs, instead of using an old standard HTML form submit to a PHP page of POST retrieval of each data element to achieve your name||value pairs.
I felt the OP has shown enough aptitude in the code presented to understand classic PHP solutions, and wanted to highlight the jQuery structure alternative.
By all the logic being generated in javascript - data retrieval, validation, sending to server, processing success and completion - makes it not a server side PHP solution.
I was talking about it being a standard javascript handler into a standard PHP receipt page (alas - url: 'myphpsubmitpage.php') that only takes name||value pairs, instead of using an old standard HTML form submit to a PHP page of POST retrieval of each data element to achieve your name||value pairs.
I felt the OP has shown enough aptitude in the code presented to understand classic PHP solutions, and wanted to highlight the jQuery structure alternative.
By all the logic being generated in javascript - data retrieval, validation, sending to server, processing success and completion - makes it not a server side PHP solution.
How is the 'formSubmit.php will access the variables (in data)
If I would use POST or GET the script will go to the $_POST array what do I need to do here?
Can I use .post() or .get() to do it? what will be the differences?
Thank you!
If I would use POST or GET the script will go to the $_POST array what do I need to do here?
Can I use .post() or .get() to do it? what will be the differences?
Thank you!
Im trying to do
$(popup_form_id).post is not a function
$(popup_form_id).post is not a function
function toggleLeadBody(id) {
var fieldName1 = "#spam_"+ id + "_body";
var fieldName2 = "#sr_" + id + "_body";
var popup_form_id = "popup_form_" + id;
var url ="sem_page.php?page=leads&sub=manage";
var element = $(fieldName2);
element.toggle();
var fElement = $(fieldName1);
//checking to see if its not been marked as spam
if ($(":hidden[name='flag']","#"+popup_form_id).val() =="no"){
fElement.toggle();
}
//sumbitting the form
fElement.submit(function(e) {
// alert("Hello world!");
//fElement.attr('flag','1');
e.preventDefault();
//"mark" the input name =flag as spam
$(":hidden[name='flag']","#"+popup_form_id).val("on");
fElement.toggle();
//$.ajax(
alert(url);
$(popup_form_id).post("sem_page.php?page=leads&sub=manage");
})
Oh sorry so Im tring to do it in the way I added it and I keep getting the firebug error:
$(popup_form_id).post is not a function
$(popup_form_id).post is not a function
please help I have a problem with the data im transfering to the page Im using .post()
and sending to a php page (that was originally handling a regular form submit with method post (attached is the )code
isn't the variable of the form is going to be in Post like when you are submitting The form what am I missing here its doesn't work as expected
Thank you!
and sending to a php page (that was originally handling a regular form submit with method post (attached is the )code
isn't the variable of the form is going to be in Post like when you are submitting The form what am I missing here its doesn't work as expected
Thank you!
$("#"+popup_form_id).submit(function(e) {
// alert("Hello world!");
//fElement.attr('flag','1');
e.preventDefault();
//"mark" the input name =flag as spam
$(":hidden[name='flag']","#"+popup_form_id).val("on");
fElement.toggle();
//$.ajax(
alert($(this).serializeArray());
$.post(url,$(this).serialize());
})
if (isset($_POST['spamIt'])){
//echo "try";
$id = $_POST['id'];
$email = $_POST['email'];
$sql= BaseModel::getSqlObject();
$query = "SELECT * FROM BlackList WHERE email_address = '$email'";
if (($result=$sql->Query($query)) === FALSE)
die(ShowError("Server Query Error"));
$num = $result->num_rows;
//check if email is not already exist in BlackList
if ($result->num_rows == 0){
$insert_query = "INSERT INTO BlackList(email_address) VALUES ('$email')";
if (($result=$sql->Query($insert_query)) === FALSE)
die(ShowError("Server Insert Query Error"));
}
$insert_query = "UPDATE ServiceRequests SET spam = 1 WHERE id = '$id'";
if (($result=$sql->Query($insert_query)) === FALSE)
die(ShowError("Server Insert Query Error service"));
die ("ok");
}
Featured Post
An intuitive utility to help find the CSS path to UI elements on a webpage. These paths are used frequently in a variety of front-end development and QA automation tasks.
One of a set of tools we're offering as a way of saying thank you for being a part of the community.
Question has a verified solution.
If you are experiencing a similar issue, please ask a related question
Many old projects have bad code, but the budget doesn't exist to rewrite the codebase. You can update this code to be safer by introducing contemporary input validation, sanitation, and safer database queries.
Originally, this post was published on Monitis Blog, you can check it
here
.
In business circles, we sometimes hear that today is the “age of the customer.” And so it is. Thanks to the enormous advances over the past few years in consumer techno…
The viewer will learn how to create and use a small PHP class to apply a watermark to an image. This video shows the viewer the setup for the PHP watermark as well as important coding language. Continue to Part 2 to learn the core code used in creat…
The viewer will learn the basics of jQuery including how to code hide show and toggles.
Reference your jQuery libraries:
(CODE)
Include your new external js/jQuery file:
(CODE)
Write your first lines of code to setup your site for jQuery…
Suggested Courses
Course of the Month7 days, 21 hours left to enroll
715 members asked questions and received personalized solutions in the past 7 days.
Join the community of 500,000 technology professionals and ask your questions.