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mysql: please explain beginning of this method. Thanks

Posted on 2011-09-28
3
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Last Modified: 2012-05-12
Hello Experts,

what does this mean?

' ( %s ) VALUES ( %s ) '

in the beginning of the method below? this is string (single quotes)... the values seems to come from the second object param...

thanks,

function insertObject( $table, &$object, $keyName = NULL ) {
		
$fmtsql = 'INSERT INTO '.$this->nameQuote($table).' (%s)VALUES(%s)'; //I am not sure how these values are obtained to do an insert

$fields = array();
	foreach (get_object_vars( $object ) as $k => $v) {
		if (is_array($v) or is_object($v) or $v === NULL) {
				continue;
			}
		if ($k[0] == '_') { // internal field
				continue;
		}
		$fields[] = $this->nameQuote( $k );
		$values[] = $this->isQuoted( $k ) ? $this->Quote( $v ) : (int) $v;
		}
		$this->setQuery( sprintf( $fmtsql, implode( ",", $fields ) ,  implode( ",", $values ) ) );
		if (!$this->query()) {
			return false;
		}
		$id = $this->insertid();
		if ($keyName && $id) {
			$object->$keyName = $id;
		}
		return true;
	}

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Question by:epifanio67
3 Comments
 
LVL 75

Accepted Solution

by:
käµfm³d   👽 earned 250 total points
ID: 36771445
This is a PHP thing, not a MySQL thing. See the printf and sprintf documentations.
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LVL 8

Assisted Solution

by:rationalboss
rationalboss earned 250 total points
ID: 36813932
When you do something like this:

echo sprintf("Hello %s (%s) -- %d","epifanio","how are you?",33); //the output will be Helo epfianio (how are you?) -- 33

%s  -- string
%d / %i -- decimal/integer
%f -- float

for more information, check the php manual: www.php.net/sprintf

printf also does the same except that it outputs it directly to the browser. sprintf returns the text so you can echo it yourself or store in a variable.

you are right about the data coming from the second parameter of sprintf.
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Author Closing Comment

by:epifanio67
ID: 36815737
got it... thank you experts
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