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Regular expression with special characters

Hello,

I want to use a regular expression to validate a password. The password must meet the next requirements:
1. at least 8 characters
2. at least one digit
3. at least one character of the set  !@#$%&+{}[]:;<>?/\

What is the regular expression for these requirements?

Regards Arne
0
adiemeer
Asked:
adiemeer
1 Solution
 
ozoCommented:
It may be simpler to use 3 separate regular expressions for each of the requirements, but if your regular expression notation supports lookahead, you might test all 3 with
(?=.{8})(?=.*\d).*[!@#$%&+{}\[\]:;<>?/\\]
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rbrideCommented:
I'd use three separate expressions, to put it into 1 is quite tricky and not worth the effort because it is hard to maintain. Here I have used perl style.

# Match at least 8 non-space characters. After the comma you can also put in the maximum length allowed, e.g. {8,20}
($pw =~ /\S{8,}/)

# At least one digit
($pw =~ /\d+/)

# and match at least one of the special characters. Note you will have to escape certain characters (done here with backslash).
($pw =~ /[!@#\$%&+{}\[\]:;<>?\\\/]+/)
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ienaxxxCommented:
^.*(?=.{8,})(?=.*\d)(?=.*[a-zA-Z])(?=.*[@#$%^&+=]).*$


look for which chars needs to be escaped in your language.

HTH. Bye!
0
 
adiemeerAuthor Commented:
Thanks, this works fine!
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