Improve company productivity with a Business Account.Sign Up

x
  • Status: Solved
  • Priority: Medium
  • Security: Public
  • Views: 196
  • Last Modified:

Help with loading xml file.

Hello,

I am using two different approaches to load the same xml file to accomodate two separate features, is there a way to only load it once?

a. Dim MyReceiver As XDocument = XDocument.Load(Server.MapPath("~/App_Data/Receiver.xml"))
b. Dim dom As New XmlDocument()
        dom.Load(Server.MapPath("~/App_Data/Receiver.xml"))

When using the first approach (a), i can't use MyReceiver.SelectNodes("//ReceiverTable")
 in my statement.

'Receiver
        Dim MyReceiver As XDocument = XDocument.Load(Server.MapPath("~/App_Data/Receiver.xml"))
        Dim LargestReceiverID = (From el In MyReceiver.Descendants("ReceiverTable") Select CInt(el.<Receiver_ID>.Value)).ToList
        ' LargestReceiverID.Sort()
        Dim CheckForItem = (From el In MyReceiver.Descendants("ReceiverTable").Elements("Receiver") Select el.Value).ToList
        If Not CheckForItem.Contains(Me.TextBox2.Text.ToString) Then
            Dim xNew As XElement = New XElement("ReceiverTable")
            xNew.Add(New XElement("Receiver_ID", (LargestReceiverID.Last() + 1)))
            xNew.Add(New XElement("Receiver", Me.TextBox2.Text.ToString))
            MyReceiver.Root.Add(xNew)
            MyReceiver.Save(Server.MapPath("~/App_Data/Receiver.xml"))
        End If
        Dim search As String = TextBox2.Text
        Dim searchId As String = Nothing
        Dim dom As New XmlDocument()
        dom.Load(Server.MapPath("~/App_Data/Receiver.xml"))
        Dim list As XmlNodeList = dom.SelectNodes("//ReceiverTable")
        If CheckForItem.Contains(Me.TextBox2.Text.ToString) Then
            For Each node As XmlNode In list
                If node("Receiver").InnerText.Equals(search) Then
                    searchId = node("Receiver_ID").InnerText
                    Exit For
                End If
            Next
        End If
0
vcharles
Asked:
vcharles
  • 3
  • 3
1 Solution
 
binaryevoCommented:
Try using this or a variant of this...  Linq makes it much cleaner.

string filePath = HttpContext.Current.Server.MapPath(SettingsModel.XMLFileLocation + "Moody.xml");
            if (File.Exists(filePath))
            {
                var xml = (from x in XElement.Load(filePath).Elements("Moody")
                           select new XMLModel
                           {
                               ID = x.Element("ID").Value,
                               Value = x.Element("Value").Value
                           });
                return xml;
            }
            else
            {
                throw new Exception("File Path is invalid or file doesnt exist.");
            }
0
 
vcharlesAuthor Commented:
Can you please send me the code in VB.NET.

Thanks,

Victor
0
 
binaryevoCommented:
It would look something like this:

 
Dim filePath As String = "Moody.xml"

        If System.IO.File.Exists(FilePath) Then

            Dim xml = From x In XElement.Load(filePath).Elements("Moody")
                                   Select New XMLModel
                                   {
                                       ID = x.Element("ID").Value,
            Value = x.Element("Value").Value
                                   }


        Else
                'Handle your error here
        End If

Open in new window

0
What Kind of Coding Program is Right for You?

There are many ways to learn to code these days. From coding bootcamps like Flatiron School to online courses to totally free beginner resources. The best way to learn to code depends on many factors, but the most important one is you. See what course is best for you.

 
binaryevoCommented:
Be sure to turn Option Infer On also
0
 
theHollowCommented:
Hi
I haven't verified this, but you may wanna try going via the "DocumentElement" on the XmlDocument.

Dim dom As XmlDocument
Dim root As XmlNode

dom = New XmlDocument()
dom.Load(Server.MapPath("~/App_Data/Receiver.xml"))
root = dom.DocumentElement

Open in new window


Now, you may be able to use "root.SelectNodes("//ReceiverTable")"

Hope it helped :-)
0
 
vcharlesAuthor Commented:
Thanks, I will try it and get back to you.
0
 
vcharlesAuthor Commented:
Hi,

I;m a bit confused, do I need to replace option a below with your code?

a. Dim MyReceiver As XDocument = XDocument.Load(Server.MapPath("~/App_Data/Receiver.xml"))
b. Dim dom As New XmlDocument()
        dom.Load(Server.MapPath("~/App_Data/Receiver.xml"))

How would it impact the rest of the code related to the code?

  Dim LargestReceiverID = (From el In MyReceiver.Descendants("ReceiverTable") Select CInt(el.<Receiver_ID>.Value)).ToList
        ' LargestReceiverID.Sort()
        Dim CheckForItem = (From el In MyReceiver.Descendants("ReceiverTable").Elements("Receiver") Select el.Value).ToList
        If Not CheckForItem.Contains(Me.TextBox2.Text.ToString) Then
            Dim xNew As XElement = New XElement("ReceiverTable")
            xNew.Add(New XElement("Receiver_ID", (LargestReceiverID.Last() + 1)))
            xNew.Add(New XElement("Receiver", Me.TextBox2.Text.ToString))
            MyReceiver.Root.Add(xNew)
            MyReceiver.Save(Server.MapPath("~/App_Data/Receiver.xml"))
        End If
0
Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.

Join & Write a Comment

Featured Post

What Kind of Coding Program is Right for You?

There are many ways to learn to code these days. From coding bootcamps like Flatiron School to online courses to totally free beginner resources. The best way to learn to code depends on many factors, but the most important one is you. See what course is best for you.

  • 3
  • 3
Tackle projects and never again get stuck behind a technical roadblock.
Join Now