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Private Sub btnXYZFile_Open_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnXYZFile_Open.Click Dim XlFilePath As String Me.dlgOpenPartfile.InitialDirectory = _Default_Definition_FileOpen_Dir If Me.dlgOpenPartfile.ShowDialog(Me) = Windows.Forms.DialogResult.OK Then ' Opens the target Excel File Dim ExcelObj As New Microsoft.Office.Interop.Excel.Application ExcelObj.Visible = True End If End Sub
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