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VB.Net Image button

I have an aspx page with an image button
I set the image property of the image button to a small version of a picture.\

When someone clicks this button I want to display the full sized image in a new window.

Can someone please show me how to do this.

Thank You
0
Wildone63
Asked:
Wildone63
1 Solution
 
plusone3055Commented:
simplier way to do this is to take the original image lets say its 150 X 150
and make a copy of it
and resize it to the small version
so image1.job is 75 X 75
and onclick you display.true the original image 150 X 150

easy as pie :)



0
 
plusone3055Commented:
or do whats above with onmousover so the user doest even need to click the image :)

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MikeMCSDCommented:
Create a new page "imageViewer.aspx". Put this in the .aspx :

<head runat="server"><title></title>

<script language="javascript" type="text/javascript">
    function closewindow() {
        window.close()
    }
</script>
</head>

<body>
<form id="form1" runat="server">
<table width="100%">
<tr>
<td align="center">

<asp:Image runat="server" id="imgName" />
</td></tr>

<tr>
<td align="center"><br />
<input type="button" value="Close Window" onclick="closewindow()" />
</td></tr></table>
</form>

</body>

This in the code-behind :

 protected void Page_Load(object sender, EventArgs e)
        {
            imgName.ImageUrl = Request.QueryString["path"];

        }



Put this in your .aspx page that has the button :


<script language="JavaScript">
function oWin(iPath)
{newWin = window.open("imageViewer.aspx?path=" + iPath,"winOne","height=630,width=680,status=yes,toolbar=no,menubar=no,location=no,top=90,left=120,resizable=yes,scrollbars=yes");}
</script>


<asp:ImageButton ID="ImageButton1" ImageUrl="~/images/0000266_0.jpg"  runat="server"
 OnClientClick="oWin('~/images/0000266_0.jpg')"  />

You can adjust the size of the page and location by changing the parameters in the oWin function.
0
 
MikeMCSDCommented:
you're using VB, so this instead :

protected void Page_Load(object sender, EventArgs e)
        {
           imgName.ImageUrl = Request.QueryString("path")  
        }


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Wildone63Author Commented:
All of the answers were good.

I chose this one because it was very easy to use and had some additional benefits.

I had to purchase the java but it was 29.00. Very good deal!
0

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