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How to create an array function

Posted on 2011-09-30
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Last Modified: 2012-05-12
Is it possible to create a custom function that returns an array, so that I can assign that function to an array variable?





Note to self: If it is possible, revise XRisk() accordingly.
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Question by:Milewskp
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8 Comments
 
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Assisted Solution

by:Patrick Matthews
Patrick Matthews earned 200 total points
ID: 36894804
Yes, you can.  I typically do it by:

1) Declaring the function as Variant
2) Declaring an array variable within the function to hold the "answer"
3) Setting the return value of the function to that array variable

Then, if I call that function from elsewhere in my VB project, I make sure to declare the variable accepting the result as a Variant.
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Expert Comment

by:borgunit
ID: 36896099
A few different ways but this is one:

Function yourFunction () as variant ()
Dim vArray as variant

YOUR app

yourFunction = vArray


End function
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LVL 45

Expert Comment

by:aikimark
ID: 36901160
What version of VB is this.  In VB5 (and earlier versions) you had to return a Variant data type as noted by matthewspatrick.  In VB6, you were allowed to return an array.

What is XRisk()?
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Author Comment

by:Milewskp
ID: 36902939
Hi, aikimark
XRisk() is just the name of a function I'm using. How can I tell if I'm using VB5 or 6? Can you show me an example of a VB6 array function?
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Expert Comment

by:aikimark
ID: 36902976
click the help about menu.  The version will be displayed in the subsequent dialog box.
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Author Comment

by:Milewskp
ID: 36902990
I have VB 6.5, Version 1053? Can you show me an example of a VB6 array function?
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Accepted Solution

by:
aikimark earned 300 total points
ID: 36903132
Public Function ArrayTest(ByVal parmSize As Long) As Long()
    Dim lngLoop As Long
    Dim lngReturn() As Long
    ReDim lngReturn(1 To parmSize)
    For lngLoop = 1 To parmSize
        lngReturn(lngLoop) = lngLoop
    Next
    ArrayTest = lngReturn
End Function

Public Sub testarray()
    Debug.Print UBound(ArrayTest(100))
    Debug.Print ArrayTest(105)(3)
End Sub

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Author Closing Comment

by:Milewskp
ID: 36903691
Thanks everyone!
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