grep a file by date

you could make a bash script which takes the date as an argument and then implements it into the command?

Save as dgrep and run ./dgrep 20111003114318 to find the file. I believe the script is correct, i will test it when i get my linux machine online

#! /bin/bash
# run egrep on date
egrep -v "^$|[/]$" test_$1.txt

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can I implement in the above command.

something like  egrep -v "^$|[/]$" test_$date.txt

My solutions is to create a new file, dgrep in your current working directory. Copy/paste my code into this file, and then run chmod +x dgrep

Then you can run ./dgrep 2020204083 and it will run the search.

$1 is the reference to the first command line argument passed to the script, the name is not arbitrary

what if I automate the process rather than running it from command line

Do you need to grep filenames with specific timestamps or can you glob it?  If you need specific dates, how do you determine which dates need to be passed to the script?

it always will  be the sysdate. No worries about time. If it will able to pick up file by sysdate then it should be fine.