hour:min from datetime

I would like to select all from a DateTime column where hour is 14 and minutes 10, i.e. 14:10.
It does not matter which date it is. How is best to do this?
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Lee SavidgeCommented:
You where clause should be:

where left(convert(nvarchar(8), myDateTimeField, 108), 2) = '14'
Don't know if it's exactly the best, but it should work:

SELECT datetime FROM yourtablename WHERE datetime LIKE '%14:10%'
Lee SavidgeCommented:

where left(convert(nvarchar(8), myDateTimeField, 108), 5) = '14:10'

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You really should use DATEPART function to do it right.
For example
select * from <tablename> where DATEPART(minute, columnname) = 12
Or for your example
select * from ABook where DATEPART(hour, DateReceived) = 14 AND DATEPART(minute, DateReceived) = 10
Obviously substitute 'ABook' for your table name and 'DateReceived' for your column name in the example above.
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Microsoft SQL Server 2008

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