Cisco 877W different time in log and sh clock

My clock/ntp setup is
clock initialize nvram
clock timezone MSK 4

clock save interval 8
...
! ip nat inside source static udp 192.168.1.63 123 interface Dialer0 123
...
access-list 10 permit 192.43.244.18
...
access-list 100 remark Auto generated by SDM for NTP (123) time.nist.gov
access-list 100 permit udp host 192.43.244.18 eq ntp host 192.168.1.1 eq ntp
...
access-list 101 remark Auto generated by SDM for NTP (123) time.nist.gov
access-list 101 permit udp host 192.43.244.18 eq ntp any eq ntp
...
access-list 101 remark NTP server
access-list 101 permit udp any any eq ntp
...
kron policy-list TIME
 cli ntp server 192.43.244.18 prefer source Dialer0
!
kron occurrence TIME in 0:5 oneshot
 policy-list TIME
!
kron occurrence TIME in 5:0 recurring
 policy-list TIME
!
...
ntp access-group peer 10
ntp server 192.43.244.18 prefer source Dialer0

Moscow time is UTC/GMT +4 now and winter time is abolished in that year.
Winter time is MSK, summer time is MSD (it is MSD now).
Now in logs (deb ntp all) I see time by 4 hours less than at sh clo and sh ntp as d.
What is the reason of difference, and how to set these times equal?
Example:
Oct  4 18:24:34.051: NTP message sent to 192.43.244.18, from interface 'Dialer0' (91.79.169.31).
Oct  4 18:24:34.295: NTP message received from 192.43.244.18 on interface 'Dialer0' (91.79.169.31).
Oct  4 18:24:34.295: NTP Core(DEBUG): ntp_receive: message received
Oct  4 18:24:34.295: NTP Core(DEBUG): ntp_receive: peer is 0x83F5AAE0, next action is 1.
Oct  4 18:24:34.295: NTP Core(DEBUG): receive: packet given to process_packet
Router#sh clo
22:25:49.579 MSD Tue Oct 4 2011
Router#
Oct  4 18:27:07.049: NTP message sent to 87.108.20.70, from interface 'Dialer0' (91.79.169.31).
Oct  4 18:27:07.097: NTP message received from 87.108.20.70 on interface 'Dialer0' (91.79.169.31).
Oct  4 18:27:07.097: NTP Core(DEBUG): ntp_receive: message received
Oct  4 18:27:07.097: NTP Core(NOTICE): ntp_receive: dropping message: restricted..