Exception in eval of XPATH API Try other way A location step was expected following the '/' or '//' token.

Just from that code!? Can you possibly attach TestFile.xml to this q?

You should use \\ instead of one \

  "C:\\TestDir\\testObj\\TestFile.xml";      

You cannot use one backslash in the filepath in Java code as backshlash has a special meaning - in all cases you should use two backslashes
not only in the beginning

Missed that ;)

Much easier to do

 "C:/TestDir/testObj/TestFile.xml";      

No difference -  "C:/TestDir/testObj/TestFile.xml";       or this  "C:\\TestDir\\testObj\\TestFile.xml";      
With a single backslsh - this is a problem

I am sorry, made a mistake while typing. It does have 2 backslashes, see below.
mport javax.xml.parsers.DocumentBuilderFactory;

import org.w3c.dom.Document;
public static void main(String[] args) {
            String omxml =
                 "C:\\TestDir\\testObj\\TestFile.xml";                  File tfile = new File(omxml);
           
            try {
                   doc  = DocumentBuilderFactory.newInstance().newDocumentBuilder().parse(tfile);
                  }catch(Exception eee){
                    eee.printStackTrace();
                  }

The test file has following contents:
<?xml version="1.0" encoding="UTF-8"?>
<TestVOM>
        
      <ApplicationConfig>

      <TestWebServiceURL>http://www.test.com/Test.asmx</TestWebServiceURL>
</ApplicationConfig>
</TestVOM>

So which line is throwing this execption - and can you post the stacktrace ?
and corresponding lines which are referreed in the stacktrace ?

Its showing this in Tomcat logs:
Exception in eval of XPATH API Try other way A location step was expected following the '/' or '//' token
without any line no.

Just trying to make sure if it is being thrown elsewhere in a jar file code. Will update you. Thx

Ok, will do thx. Will let you know.

Added points for effort