Scalar-Valued function not working

Have a scalar valued function that nots working, any  help would be grand

error message is Incorrect syntax near 'Inst_Type_Code'. and I want the value  of @StrInstTypeCode  returned
MrDavidThornAsked:
Who is Participating?
I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

rajvjaCommented:
Paste your function so that its easy to trace the error
0
plummetCommented:
Yes, we need to see the function to be able to help
0
MrDavidThornAuthor Commented:
sorry thought I had paste it, have worked on it a bit more and I get the error message

Msg 102, Level 15, State 1, Procedure psInst_ID_Type, Line 17
Incorrect syntax near '='.
Msg 102, Level 15, State 1, Procedure psInst_ID_Type, Line 22
Incorrect syntax near 'END'.
CREATE FUNCTION psInst_ID_Type
(
	@Inst_Type_Code Nvarchar(10)
)
RETURNS  nvarchar(1)
AS
BEGIN

declare @return varchar(1)

select @return = case @Inst_Type_Code 
		WHEN 'EQTY' THEN ='I'
		WHEN 'BOND' THEN ='I'
		WHEN 'FUTR' THEN 'A'
		END
	RETURN @return
END

Open in new window

0
plummetCommented:
Try this:

CREATE FUNCTION psInst_ID_Type
(
	@Inst_Type_Code Nvarchar(10)
)
RETURNS  nvarchar(1)
AS
BEGIN

declare @return varchar(1)

select @return = case @Inst_Type_Code 
		WHEN 'EQTY' THEN  'I'
		WHEN 'BOND' THEN 'I'
		WHEN 'FUTR' THEN 'A'
		END
	RETURN @return
END 

Open in new window


No "=" signs in the case..when!
0

Experts Exchange Solution brought to you by

Your issues matter to us.

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Start your 7-day free trial
TempDBACommented:
Its just a small error in case statement. You are using = for assingnig the value. Use the below query

CREATE FUNCTION psInst_ID_Type  
(  
        @Inst_Type_Code Nvarchar(10)  
)  
RETURNS  nvarchar(1)  
AS  
BEGIN  
 
declare @return varchar(1)  
 
select @return = case @Inst_Type_Code  
                WHEN 'EQTY' THEN 'I'  
                WHEN 'BOND' THEN 'I'  
                WHEN 'FUTR' THEN 'A'  
                END  
        RETURN @return  
END
0
It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today
Microsoft SQL Server 2005

From novice to tech pro — start learning today.

Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.