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# Find looping between 2 lists

Posted on 2011-10-18
Medium Priority
184 Views
Hi there;

I got a C# application with 2 lists as follows:

List1 List2
1.     4
2.     3
3.     5
4.     6
5.     2
6.     1

I need to grab the conditions as follows
1 4, 4 6, 6 1
2  3, 3 5, 5 2

The starting number should end as above.

How can i find such looping in C#?

Kind regards.
0
Question by:jazzIIIlove
• 26
• 18
• 8

LVL 46

Expert Comment

ID: 36985737
Hi Jazz,

It's pretty easy to "walk" through a list of pointers.  The trick is knowing when to stop.  In your case, it could be that you quit walking after 3 nodes, when the new index is less than the current index, when the new index is less than the first index, or any of several other keys.

The example below walks you through the arrays.  It's just one of many possible solutions.

Good Luck,
Kent

int List1[7] = { 1, 2, 3, 4, 5, 6, 0 };
int List2[7] = { 4, 3, 5, 6, 2, 1, 0 };

int WalkArray (int start)
{
int current;
int new;

current = start;
while (1)
{
new = List2[Current];
if (new < current)
break;
printf (" Start = %d, Nodes = %d,%d\n", start, current, new);
current = new;
}
}
0

LVL 12

Author Comment

ID: 36985821
Ah, you haven't used List1 to compare?
0

LVL 12

Author Comment

ID: 36986029
I believe that you haven't realize there is a loop between those 2 lists.

Kind regards.
0

LVL 86

Expert Comment

ID: 36986738
Try something like this out:
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}

private int StartingIndex = 1; // <-- Set the "starting index"

private int Index = -1; // <-- Sentinel value of -1

// Arrays in .Net are ZERO based so we have to pad them with a dummy value at Index 0 (zero):
private int[] List1 = {-1, 1, 2, 3, 4, 5, 6 };
private int[] List2 = {-1, 4, 3, 5, 6, 2, 1 };

private void timer1_Tick(object sender, EventArgs e)
{
if (Index == -1)
{
Index = StartingIndex;
}

int NextIndex = List2[Index];

listBox1.Items.Add(Index.ToString() + " --> " + NextIndex.ToString());

Index = NextIndex;
}
}

Output: Idle-Mind-513187.flv
0

LVL 46

Expert Comment

ID: 36986791
Hi Jazz,

You don't need List1, except as the starting point.

int List1[7] = { 1, 2, 3, 4, 5, 6, 0 };
int List2[7] = { 4, 3, 5, 6, 2, 1, 0 };

Note that the zero should be first in the array, not last, but that doesn't change how you walk through it.

int List1[7] = {0, 1, 2, 3, 4, 5, 6};
int List2[7] = {0, 4, 3, 5, 6, 2, 1};

When you start at 1, you fetch a 4 from List2.  Now there's no need to go back to List1 as the 4 is the node that you want in List2.  List2[4] contains a 6, which becomes the next node.  List2[6] contains a 1, which signals that you've hit the end of the list.

Kent
0

LVL 12

Author Comment

ID: 36987186
Hi kdo;

Thanks for the interest but simply i failed to utlize your idea to code sadly.

Give a hand?

Regards.
0

LVL 46

Expert Comment

ID: 36987532

I'll be glad to lend a hand.  Where do we start?

Kent
0

LVL 12

Author Comment

ID: 36987667
Need a code?

Regards.
0

LVL 86

Expert Comment

ID: 36987706
Did you look at my post at all?...

The crux of it is here:

int NextIndex = List2[Index];

listBox1.Items.Add(Index.ToString() + " --> " + NextIndex.ToString());

Index = NextIndex;

I grab the "next" index using the "current" index and then do something with it.  Afterwards I set the current index to the next index value.

That's really all there is to it.

How is this going to be used in your actual application?  Perhaps understanding that would give us insight into what you're after...
0

LVL 12

Author Comment

ID: 36988379
Hi there Idle_Mind:

Sorry for my delay, i checked your code but i don't think this is what i want:

int[] List1 = {-1, 1, 2, 3, 4, 5, 6 };
int[] List2 = {-1, 4, 3, 5, 6, 2, 1 };

As the lists are like this, my aim is to grab 5,2 (5th element of the lists) and 6,1.

The rule is:
1 4
4 6
6 1

one loop starting with 1 ending with 1.
->2<- 3
3 5
5 ->2<-
another loop starting and ending with 2

Regards.
0

LVL 86

Expert Comment

ID: 36988403
I just showed how to deal with the first loop.  Did you watch the output in the ListBox?

For two loops, you'd just need to add another variable to track the index for that loop.

The loops are independent of each other right?

Again, how is this going to be used?
0

LVL 46

Expert Comment

ID: 36988538
Hi Jazz,

int[] List1 = {-1, 1, 2, 3, 4, 5, 6 };
int[] List2 = {-1, 4, 3, 5, 6, 2, 1 };

Now key on the items in List2.  There are two chains within the list

int[] List1 = {-1, 1, 2, 3, 4, 5, 6 };
int[] List2 = {-1, x, 3, 5, x, 2, x };

and

int[] List1 = {-1, 1, 2, 3, 4, 5, 6 };
int[] List2 = {-1, 4, x, x, 6, x, 1 };

No matter where you start in the table, you'll follow one of these chains.  All that List1 does is establish a starting point.  List1 defines every node so that:

List1[n] = n;

You could jumble the items in List1 into any order that you like.  All it will do is jumble where a loop through a chain begins.  The chaining is self contained within List2.

Kent
0

LVL 86

Expert Comment

ID: 36988685
Does this help illustrate better?

It shows how each starting position "chains":
private int[] List1 = { -1, 1, 2, 3, 4, 5, 6};
private int[] List2 = { -1, 4, 3, 5, 6, 2, 1 };

private void timer1_Tick(object sender, EventArgs e)
{
ListBox LB;
int NextIndex;
for (int i = 1; i <= List1.GetUpperBound(0); i++)
{
NextIndex = List2[List1[i]];

LB = (ListBox)this.Controls["listBox" + i.ToString()];
LB.Items.Add(List1[i].ToString() + " --> " + NextIndex.ToString());

List1[i] = NextIndex;
}
}
Idle-Mind-513275.flv
0

LVL 12

Author Comment

ID: 36988848
you are going to hate me but:

When I do this, I couldn't see the loop;

I mean I just want to output the forwarding loop:

There is a loop, 1 4, 4 6, 6 1
...

but not 4 6, 6 1, 1 4 as it's already covered in the above loop.

Regards.
private static List<int> List1 = new List<int> { 1, 2, 3, 4, 5, 6 };
private static List<int> List2 = new List<int> { 4, 3, 5, 6, 2, 1 };

static void Main(string[] args)
{
int NextIndex;
for (int i = 1; i <= List1.Max(); i++)
{
NextIndex = List2[List1[i]];

Console.WriteLine(i.ToString());
Console.WriteLine(List1[i].ToString() + " --> " + NextIndex.ToString());

List1[i] = NextIndex;
}
0

LVL 86

Expert Comment

ID: 36989014
Look at this output:
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace ConsoleApplication1
{
class Program
{

private static List<int> List1 = new List<int> { 0, 1, 2, 3, 4, 5, 6, 7, 8, 9};
private static List<int> List2 = new List<int> { 0, 4, 3, 5, 6, 2, 1, 8, 7, 9};

static void Main(string[] args)
{
List<List<int>> loops = new List<List<int>>();

for (int i = 1; i < List1.Count; i++)
{
OutputLoop(i);
}

Console.Write("Press Enter to Quit");
}

private static void OutputLoop(int StartingIndex)
{
Console.Write("Loop #" + StartingIndex.ToString() + ": ");
int counter = 0;
int Index = StartingIndex;
int NextIndex;
do
{
NextIndex = List2[Index];
Console.Write(Index.ToString() + " --> " + NextIndex.ToString() + "   ");
Index = NextIndex;
counter++;
} while (Index != StartingIndex && counter < List2.Count);
Console.WriteLine("");
}

}
}
0

LVL 86

Expert Comment

ID: 36989039
...and what about something like this?

private static List<int> List1 = new List<int> { 0, 1, 2, 3};
private static List<int> List2 = new List<int> { 0, 2, 1, 1};

The first two are:

1 --> 2, 2 --> 1
2 --> 1, 1 --> 2

But the last one is:

3 --> 1, 1 --> 2, 2 --> 1

The third loop includes the first two, but is not equal to them.
0

LVL 12

Author Comment

ID: 36989216
good, thanks, the looping should be just forward.

in the case
List 1: 0, 1, 2, 3
List 2: 0, 2, 1, 1

1 2, 2 1 done

but if the following is the case;
List 1: 0, 1, 2, 4
List 2: 0, 2, 4, 1

1 2, 2 4, and 4, 1 so there is a loop.
0

LVL 12

Author Comment

ID: 36989890
unfortunately, your code fails for the given lists:
private static List<int> List1 = new List<int> { 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 13, 14, 15, 17, 19, 20, 21, 22, 23 };
private static List<int> List2 = new List<int> { 0, 3, 3, 6, 5, 2, 2, 9, 8, 11, 1, 13, 14, 12, 19, 18, 20, 16, 22, 21, 23 };

I will provide my code tomorrow.

Kind regards.

P.S. Maybe, i couldn't define the problem well...
0

LVL 86

Expert Comment

ID: 36990217
There are only 21 slots in the arrays, using indexes 0 thru 20, so how can you jump to positions 21, 22, or 23?!
0

LVL 12

Author Comment

ID: 36991081
hmm, you are right. My mistake, sorry.
0

LVL 12

Author Comment

ID: 37003475
Ok, one final thing is that i got lost in the output and cannot find a way in your code to output the start of the loop which is e.g.:

1 3
2 4
3 4
4 1

The first occurence of the loop is as:
1 3
3 4
4 1

The output should be 1 3 line as it's the first loop occuring (precedence over the 2. line).

So the output should be just 1 3 (just) but i couldn't solve it how i can do this in your code.

Kind regards and thanks for your interest, moreover patience.
0

LVL 86

Expert Comment

ID: 37003586
So you want the pair in the loop sequence that has the lowest starting value?
0

LVL 12

Author Comment

ID: 37003860
yep, bulls eye.
0

LVL 12

Author Comment

ID: 37003897
Ok, one final thing is that i got lost in the output and cannot find a way in your code to output the start of the loop which is e.g.:

1 3
2 4
3 4
4 1

1 3
3 4
4 1

The output should be 1 3 line as it's the first loop occuring (precedence over the 2. line).

So the output should be just 1 3 (just) but i couldn't solve it how i can do this in your code.

Kind regards and thanks for your interest, moreover patience.
0

LVL 86

Expert Comment

ID: 37004332
Try this out:
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace ConsoleApplication1
{
class Program
{

private static List<int> List1 = new List<int> { 0, 1, 2, 3, 4, 5, 6};
private static List<int> List2 = new List<int> { 0, 4, 3, 5, 6, 2, 1};

static void Main(string[] args)
{
Dictionary<string, List<string>> loops = new Dictionary<string, List<string>>();

List<string> loop;
List<string> tmpLoop;
for (int i = 1; i < List1.Count; i++)
{
loop = OutputLoop(i);

tmpLoop = new List<string>();
tmpLoop.Sort();

if (!loops.ContainsKey(tmpLoop[0]))
{
}
}

Console.WriteLine("Unique Loops:");
foreach (KeyValuePair<string, List<string>> UniqueLoop in loops)
{
Console.WriteLine("Starts with: " + UniqueLoop.Key + "  |  Sequence: " + String.Join(", ", UniqueLoop.Value.ToArray()));
}

Console.Write("Press Enter to Quit");
}

private static List<string> OutputLoop(int StartingIndex)
{
List<string> loop = new List<string>();

int counter = 0;
int Index = StartingIndex;
int NextIndex;
do
{
NextIndex = List2[Index];
loop.Add(Index.ToString() + " " + NextIndex.ToString());
Index = NextIndex;
counter++;
} while (Index != StartingIndex && counter < List2.Count);
return loop;
}

}
}
0

LVL 12

Author Comment

ID: 37005670
ah, above fails for longer lists regarding index out of bound but I couldn't find out the solution to this problem.

Kind regards.
0

LVL 46

Expert Comment

ID: 37005755
Hi Jazz,

Post the longer list that is failing.

The first item is zero because C uses "relative zero" referencing.  If you want List[x] to be position x in the array, you need to put a dummy element in the front of the array as a place holder.

Kent
0

LVL 12

Author Comment

ID: 37005799
List1 List2
1      3
2      3
3      6
4      5
5      2
6      2
7      9
9      11
10      1
11      13
13      14
14      12
15      19
17      18
19      20
20      16
21      22
22      21
23      23
24      23

Regards.
0

LVL 46

Expert Comment

ID: 37005816
Hi Jazz,

The largest element in each of those lists is larger than the number of items in the list.

I count 19 items in each.  Since C uses "relative 0" indexing, the largest value in the list can only be 18.

Kent
0

LVL 86

Expert Comment

ID: 37006629
Assuming you provide VALID input Arrays, this should handle finding the "starting pair" better than the previous approach which used a string comparison:
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace ConsoleApplication1
{
class Program
{

private static List<int> List1 = new List<int> { 0, 1, 2, 3, 4, 5, 6 };
private static List<int> List2 = new List<int> { 0, 4, 3, 5, 6, 2, 1 };

static void Main(string[] args)
{
Dictionary<string, Sequence> Sequences = new Dictionary<string, Sequence>();

Sequence sq;
for (int i = 1; i < List1.Count; i++)
{
sq = GenerateSequence(i);

if (!Sequences.ContainsKey(sq.StartingPair.ToString()))
{
}
}

Console.WriteLine("Unique Sequences:");
foreach (KeyValuePair<string, Sequence> UniqueLoop in Sequences)
{
Console.WriteLine("Starts with: " + UniqueLoop.Key.ToString() + "  |  Sequence: " + UniqueLoop.Value.ToString());
}

Console.WriteLine("");
Console.Write("Press Enter to Quit");
}

private static Sequence GenerateSequence(int StartingIndex)
{
List<SequencePair> sequence = new List<SequencePair>();
int counter = 0;
int Index = StartingIndex;
int NextIndex;
do
{
NextIndex = List2[Index];
Index = NextIndex;
counter++;
} while (Index != StartingIndex && counter < List2.Count);

return new Sequence(sequence);
}

}

public class Sequence
{

public SequencePair StartingPair = null;
public List<SequencePair> Pairs;

public Sequence(List<SequencePair> Pairs)
{
this.Pairs = Pairs;
foreach (SequencePair sp in Pairs)
{
if (this.StartingPair == null || sp.value1 < StartingPair.value1)
{
this.StartingPair = sp;
}
}
}

public override string ToString()
{
System.Text.StringBuilder sb = new StringBuilder();
foreach (SequencePair sp in this.Pairs)
{
sb.Append(sp.ToString() + ", ");
}
return sb.ToString().TrimEnd(", ".ToCharArray());
}
}

public class SequencePair
{

public int value1;
public int value2;

public SequencePair(int value1, int value2)
{
this.value1 = value1;
this.value2 = value2;
}

public override string ToString()
{
return value1.ToString() + " " + value2.ToString();
}

}

}
0

LVL 12

Author Comment

ID: 37006862
Kdo:
Ok, but no way to fix this as I was losing my mind to find a way for this...

Idle_Mind:
I will check soon, and my list is integer for the record. It won't hurt, right?

Kind regards.
0

LVL 86

Expert Comment

ID: 37006881
"... but no way to fix this"

Where are you getting your input from?
0

LVL 46

Expert Comment

ID: 37006887

Fix it?  Just make sure that the array has at least as many elements as the largest value that you're going to store.

I'm curious about your application.  How did you happen to get ahold of it?

Kent
0

LVL 12

Author Comment

ID: 37007159
Idle_Mind:

from a database table having 2 integer columns, I just read the content...

Regards.

Kdo:

>> Just make sure that the array has at least as many elements as the largest value that you're going to store.

So, largest value in the list is 25, the list must have 25 elements (so no skip during the increment of the value)

1
3
4
5
..fails. True?

Regards.
0

LVL 86

Expert Comment

ID: 37007201
The current implementations have assumed that the numbers correlate with an absolute Index value in the Arrays.

List1:  1,  2,  3,  4,  5,  6,  7,  9, 10, 11, 13, 14, 15, 17, 19, 20, 21, 22, 23, 24
List2:  3,  3,  6,  5,  2,  2,  9, 11,  1, 13, 14, 12, 19, 18, 20, 16, 22, 21, 23, 23

We could instead search List1 for the matching "next value" entry from List2 and then take the corresponding value in List2 that is at the same Index of the found entry in List1.

This doesn't make sense either, though, since List1 doesn't have an entry for 12, 18, or 16.

So what would you expect to get back from those inputs?

I see:

1 3, 3 6, 6 2, 2 3, 3 6, 6 2, ...
2 3, 3 6, 6 2, ...
3 6, 6 2, 2 6, ...
4 5, 5 2, 2 3, 3 6, 6 2, ...
5 2, 2 3, 3 6, 6 2, ...
6 2, 2 3, 3 6 , ...

7 9, 9 11, 11 13, 13 14, 14 12, ???
9 11, 11 13, 13 14, 14 12, ???

10 1, 1 3, 3 6, 6 2, 2 3, ...

11 13, 13 14, 14 12, ???
13 14, 14 12, ???
15 19, 19 20, 20 16, ???
17 18, ???
19 20, 20 16, ???
20 16, ???

21 22, 22 21, ...
22 21, 21 22, ...

23 24, 24 23, ...
24 23, 23 24, ...
0

LVL 46

Expert Comment

ID: 37007815
>>>> Just make sure that the array has at least as many elements as the largest value that you're going to store.

>>So, largest value in the list is 25, the list must have 25 elements (so no skip during the increment of the value)

25 + 1

Element 0 (list[0]) has to be allocated, too.

Kent
0

LVL 12

Author Comment

ID: 37009208
Idle_Mind; just forwarding ones,  turning back in the list.
1 3, 3 6, 6 2, 2 3, 3 6, 6 2, ...
2 3, 3 6, 6 2, ...
3 6, 6 2, 2 6, ...

This loop is not true as 1 3 6 2 is not the regular list 2 cannot come after 2.

Regards.
0

LVL 86

Expert Comment

ID: 37009263
?...

Not following you there sorry.

Given those lists, what output were you expecting to get?
0

LVL 12

Author Comment

ID: 37009418
I will give the most definitive comment tomorrow.

Regards and thanks for not giving up.
0

LVL 12

Author Comment

ID: 37012017
Ok, my mistake

In fact the lists are just the extraction of a table record of an MSSQL database,

both lists are indicating the columns which form a composite key.

The list1 is incremental but a row may be deleted by the user.
a  b   c    d   e   f   g   h
List1:  1,  2,  3,  4,  5,  6,  7,  9, 10, 11, 13, 14, 15, 17, 19, 20, 21, 22, 23, 24
List2:  3,  3,  6,  5,  2,  2,  9, 11,  1, 13, 14, 12, 19, 18, 20, 16, 22, 21, 23, 23

Given the lists above

1 3 3 6 6 6 2 is not forming a loop,  (a, c, f) You cannot go back as 2 6 (which is b), you have to go forward, and the output of the program should be the first row which is 1 3(a)

2 3 3 6 6 2  is another loop (b, c, f) and the output of the program should be as 2 3

3 6 6 2 is another loop but a loop within loop, so it shouldn't be outputted.

4 5 5 2 is not a loop

7 9 9 11 11 13 13 14 14 12 is not a loop

15 19 19 20 20 16 is not a loop

21 22 22 21 is a loop

23 23 is a loop

23 23 24 23 is another loop (not an inner loop as it's different than above, 23 23)

Hope this clarifies.

Kind regards.
0

LVL 12

Author Comment

ID: 37012067
I had asked a similar question but with MSSQL idea, here you;
http://mobile.experts-exchange.com/Q_27400368.html
Same rules are applying there too.

Kind regards.
0

LVL 86

Expert Comment

ID: 37012288
Ok...so 1 3 3 6 6 6 2 return 1 3.

...wouldn't 4 5 5 2 2 3 3 6 6 2 return 4 5 then?

They both are "not loops?

21 22 22 21 is a loop but it doesn't return anything?  Wouldn't it return 21 22?

22 21 21 22 would be omitted right?  (since it's a duplicate of  21 22)

Does 23 23 return 23 23?

24 23 23 23 would return 24 23?  (based on the first example returning 1 3)

Do you need to assign a property to these things to indicate the possible return states?
(1) Complete loop - starts and ends on the same number
(2) Duplicate loop
(4) Does not loop

0

LVL 12

Author Comment

ID: 37012606
...wouldn't 4 5 5 2 2 3 3 6 6 2 return 4 5 then?

No, in this context, after the second 5, you cannot go back to 2, so, no.

21 22 22 21 is a loop and woukd return 21 22

23 23 will return 23 23 in this context.

>>24 23 23 23 would return 24 23? Â (based on the first example returning 1 3)

yes.

Ok...so 1 3 3 6 6 6 2 return 1 3.

...wouldn't 4 5 5 2 2 3 3 6 6 2 return 4 5 then?

They both are "not loops?

21 22 22 21 is a loop but it doesn't return anything? Â Wouldn't it return 21 22?

22 21 21 22 would be omitted right? Â (since it's a duplicate of Â 21 22)

Does 23 23 return 23 23?

24 23 23 23 would return 24 23? Â (based on the first example returning 1 3)

Do you need to assign a property to these things to indicate the possible return states?
(1) Complete loop - starts and ends on the same number
(2) Duplicate loop
(4) Does not loop

No need to output 3 and 4

Duplication of a loop can/should be omitted.

For 1, yes.

I believe that the question gets longer because of my lacking explanation, sorry for this.

Regards.

0

LVL 86

Expert Comment

ID: 37012640
Still don't understand why these two are different:

1 3 3 6 6 2 2 3
4 5 5 2 2 3 3 6 6 2

The first one starts with 1 3, loops 3 6 6 2 2 3, and returns 1 3.

The second one starts with 4 5 5 2, loops 2 3 3 6 6 2 and returns nothing?
0

LVL 12

Author Comment

ID: 37012953
1 3 3 6 6 2
from 6 to 2, not allowed, you are going back

Even from 6 to 2, there is a loop, it's not allowed in this context. Forward, always forward.

1 3 3 6 6 7 7 1

see, forward, so valid.

In your examples, you are going back for the transition, always forward.

Regards.

So 4 5 5 2 is a dead end, cannot be considered as a loop, because you want to go back to 2, not allowed.

Hope it's clear, I am terribly sorry, Idle_Mind, you are a good guy, still stick to this question, I really appreciate your effort and interest.

You are a good guy...

Regards.
0

LVL 86

Expert Comment

ID: 37012978
No, no...I see it now.  Got it!  So only the last number, forming the actual loopback, can be less than the previous number.

I'll see if I can modify the code to take that into account.
0

LVL 12

Author Comment

ID: 37012988
I asked too many questions, but u are the one who is the most patient one, 42 comments, we have had and u still stay in my question, if any admin watches out this thread, i hereby declare u as the most patient one in EE.

How come? :)

Regards.
0

LVL 12

Author Comment

ID: 37012990
Ok this is not being patient but passion :)
0

LVL 86

Accepted Solution

Mike Tomlinson earned 2000 total points
ID: 37013155
See if this one works as expected:
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace ConsoleApplication1
{
class Program
{

private static List<int> List1 = new List<int> { 1, 2, 3, 4, 5, 6, 7, 9, 10, 11, 13, 14, 15, 17, 19, 20, 21, 22, 23, 24 };
private static List<int> List2 = new List<int> { 3, 3, 6, 5, 2, 2, 9, 11, 1, 13, 14, 12, 19, 18, 20, 16, 22, 21, 23, 23 };

static void Main(string[] args)
{
Dictionary<string, Sequence> Sequences = new Dictionary<string, Sequence>();

Sequence sq;
for (int i = 1; i < List1.Count; i++)
{
sq = GenerateSequence(List1[i]);
if (sq != null)
{
if (!Sequences.ContainsKey(sq.StartingPair.ToString()))
{
}
}
}

Console.WriteLine("Unique Sequences:");
foreach (KeyValuePair<string, Sequence> UniqueLoop in Sequences)
{
Console.WriteLine("Starts with: " + UniqueLoop.Key.ToString() + "  |  Sequence: " + UniqueLoop.Value.ToString());
}

Console.WriteLine("");
Console.Write("Press Enter to Quit");
}

private static Sequence GenerateSequence(int StartingValue)
{
List<SequencePair> sequence = new List<SequencePair>();
int counter = 0;
int Value = StartingValue;
int NextValue;
int NextValueIndex;
do
{
NextValueIndex = List1.IndexOf(Value);
if (NextValueIndex != -1)
{
NextValue = List2[NextValueIndex];
if (NextValue >= Value)
{
Value = NextValue;
}
else
{
foreach (SequencePair sp in sequence)
{
if (sp.value1 == NextValue)
{
// we found a loop!
return new Sequence(sequence);
}
}
return null;
}
}
else
{
return null;
}

counter++;
} while (Value != StartingValue && counter < List2.Count);

return new Sequence(sequence);
}

}

public class Sequence
{

public SequencePair StartingPair = null;
public List<SequencePair> Pairs;

public Sequence(List<SequencePair> Pairs)
{
this.Pairs = Pairs;
foreach (SequencePair sp in Pairs)
{
if (this.StartingPair == null || sp.value1 < StartingPair.value1)
{
this.StartingPair = sp;
}
}
}

public override string ToString()
{
System.Text.StringBuilder sb = new StringBuilder();
foreach (SequencePair sp in this.Pairs)
{
sb.Append(sp.ToString() + ", ");
}
return sb.ToString().TrimEnd(", ".ToCharArray());
}
}

public class SequencePair
{

public int value1;
public int value2;

public SequencePair(int value1, int value2)
{
this.value1 = value1;
this.value2 = value2;
}

public override string ToString()
{
return value1.ToString() + " " + value2.ToString();
}

}

}
0

LVL 12

Author Comment

ID: 37024980
This question is my shame but concluded with a success definitely.

Regards.
0

LVL 86

Expert Comment

ID: 37025046
Glad that worked for you.  =)
0

LVL 12

Author Comment

ID: 37099207
Patient you are Idle_Mind! Thanks!
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