Date in Perl

How to get the day before yesterday date in Perl.

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localtime() - 3600 * 2
new_perl_userAuthor Commented:

I did like this;

$date = localtime() - 3600 * 2;

print "$date\n";

Result: -7200
new_perl_userAuthor Commented:
Got it as:

my $yesterday = localtime(time()-48*60*60)
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that is what I meant ;)
Note that if daylight saving time applies in your locale, there may be 4 hours during the year, near midnight, when that would produce an incorrect answer.

This script resolves the DST issues...

use Time::Local;
my $today = timelocal 0, 0, 12, ( localtime )[3..5];
my ($d, $m, $y) = ( localtime $today-(86400*2) )[3..5];
printf "Day before yesterday: %d-%02d-%02d\n", $y+1900, $m+1, $d;
localtime time-(36+(localtime)[2])*60*60  
suffices to resolve the DST issue without need of modules

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