How to get just the file name from a file path

Hi guys,

I need a little bit of help here with a shell script that I have attached.

At the moment, it is returning $inputfile1 and $inputfile2 as:

Is there a way to just get the file names without the path?(i.e Invoiced123.csv and Shipped123.csv)

I require just the filenames for the parameters of my perl script.

Thanks in advance.





umask 0002

for file in `find "$BASEDIR/input/" -name "Invoiced*" -printf "%f\n"` ; do


	/cus/imports/ $inputfile1 $inputfile2

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inputfile1=`basename $BASEDIR/input/Invoiced*`

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Jason_SutionoAuthor Commented:
Thanks ozo thats all I need :D

/cus/imports/ ${inputfile1##*/} ${inputfile2##*/}

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