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I think the formula on part a is P(n,r)=n!/(n-r)!
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I think the formula on part a is P(n,r)=n!/(n-r)!

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According to my formula the answer is still wrong<br />
P(n,r)=n!/(n-r)!<br />
P(20,3) = 20*19*18*17*16*15*14*13*12<wbr />*11*10*9*8<wbr />*7*6*5*4*4<wbr />*3*2*1/(20<wbr />-3)!<br />
<br />
so its a 20*19*18=6,840<br />
<br />
Can you please show it the part 2 I still dont get it.<br />

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According to my formula the answer is still wrong
P(n,r)=n!/(n-r)!
P(20,3) = 20*19*18*17*16*15*14*13*12*11*10*9*8*7*6*5*4*4*3*2*1/(20-3)!

so its a 20*19*18=6,840

Can you please show it the part 2 I still dont get it.


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Sorry i made a mistake in my text<br />
<br />
According to the first formula<br />
P(n,r)=n!/(n-r)!<br />
P(20,3) = 20*19*18*17*16*15*14*13*12<wbr />*11*10*9*8<wbr />*7*6*5*4*4<wbr />*3*2*1/(20<wbr />-3)!<br />
<br />
so its a 20*19*18=6,840<br />
<br />
Can you please show it the part 2 I still dont get it.
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Sorry i made a mistake in my text

According to the first formula
P(n,r)=n!/(n-r)!
P(20,3) = 20*19*18*17*16*15*14*13*12*11*10*9*8*7*6*5*4*4*3*2*1/(20-3)!

so its a 20*19*18=6,840

Can you please show it the part 2 I still dont get it.

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Can any one please explain this question ? Thanks.<br />
<br />
A committee of three is chosen from a group of 20 people. How many different committees are possible, if<br />
<br />
a. the committee consists of a president, vice president, and treasurer ?<br />
b. there is no distinction among the three members of the committee ?<br />
<br />
Answer: P(20,3)=6,840 (b) 2.6.5=60
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Can any one please explain this question ? Thanks.

A committee of three is chosen from a group of 20 people. How many different committees are possible, if

a. the committee consists of a president, vice president, and treasurer ?
b. there is no distinction among the three members of the committee ?

Answer: P(20,3)=6,840 (b) 2.6.5=60

Permutation and Combination

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Math / Science

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