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MySQL SHOW COLUMNS but only those I select using PHP?

I am using the following code to generate a csv file and as you can see the SHOW COLUMNS MySQL query is used to generate the Column headings in the CSV. How do I get this query to display just the columns I have specified in the second query instead of all the table headings?

<?php
$host = 'localhost';
$user = 'mysqlUser';
$pass = 'myUserPass';
$db = 'myDatabase';
$table = 'products_info';
$file = 'export';

$link = mysql_connect($host, $user, $pass) or die("Can not connect." . mysql_error());
mysql_select_db($db) or die("Can not connect.");

$result = mysql_query("SHOW COLUMNS FROM ".$table."");
$i = 0;
if (mysql_num_rows($result) > 0) {
while ($row = mysql_fetch_assoc($result)) {
$csv_output .= $row['Field']."; ";
$i++;
}
}
$csv_output .= "\n";

$values = mysql_query("SELECT COLUMN1, COLUMN2, COLUMN3 FROM ".$table."");
while ($rowr = mysql_fetch_row($values)) {
for ($j=0;$j<$i;$j++) {
$csv_output .= $rowr[$j]."; ";
}
$csv_output .= "\n";
}

$filename = $file."_".date("Y-m-d_H-i",time());
header("Content-type: application/vnd.ms-excel");
header("Content-disposition: csv" . date("Y-m-d") . ".csv");
header( "Content-disposition: filename=".$filename.".csv");
print $csv_output;
exit;
?>

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Guy Hengel [angelIII / a3]

why not just skip that first part, and use the queries results?

<?php
$host = 'localhost';
$user = 'mysqlUser';
$pass = 'myUserPass';
$db = 'myDatabase';
$table = 'products_info';
$file = 'export';

$link = mysql_connect($host, $user, $pass) or die("Can not connect." . mysql_error());
mysql_select_db($db) or die("Can not connect.");

$values = mysql_query("SELECT COLUMN1, COLUMN2, COLUMN3 FROM ".$table."");
$row = 0;
while ($rowr = mysql_fetch_assoc($values)) 
{
  if ($row == 0)
  {
    foreach($rowr as $name => $value)
    {
      $csv_output .= $name . "; ";
    }
    $csv_output .= "\n";
  }

  for ($j=0;$j<$i;$j++) 
  {
    foreach($rowr as $name => $value)
    {
      $csv_output .= $value . "; ";
    }
  }
  $csv_output .= "\n";
}

$filename = $file."_".date("Y-m-d_H-i",time());
header("Content-type: application/vnd.ms-excel");
header("Content-disposition: csv" . date("Y-m-d") . ".csv");
header( "Content-disposition: filename=".$filename.".csv");
print $csv_output;
exit;
?>

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pda4me

ASKER

when I do that it prints the column names where the data should be?

ASKER CERTIFIED SOLUTION

Guy Hengel [angelIII / a3]

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pda4me

ASKER

That is AWESOME! Thanks!

pda4me

ASKER

AWESOME!!!

Ovid Burke

Try:

$csv_output = '';

$sql = mysql_query("SELECT column_1, column_3, column_3 FROM table") or die( 'Error' . mysql_error() );

$row = mysql_fetch_assoc($sql);

$i = 0;
while($row = mysql_fetch_assoc($sql))
{
	if( $i == 0 )
	{
		foreach($row as $key=>$val)
		{
			$csv_output .= $key . ',';
		}
		$csv_output = rtrim($csv_output, ',') . "\r";
	}
	else
	{
		foreach($row as $key=>$val)
		{
			$csv_output .= $val . ',';
		}
		$csv_output = rtrim($csv_output, ',') . "\r";
	}
	$i++;
}

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