asked on

Adding days to php date

I've got this example from a website:

<?php
$currentDate = date("Y-m-d");// current date

echo "Current Date: ".$currentDate." ";

//Add one Date
$date = strtotime(date("Y-m-d", strtotime($currentDate)) . " +1 day");
echo $date . " ";

$date = strtotime(date("Y-m-d", strtotime($currentDate)) . " +1 week");
echo $date . " ";
$date = strtotime(date("Y-m-d", strtotime($currentDate)) . " +2 week");
echo $date . " ";
$date = strtotime(date("Y-m-d", strtotime($currentDate)) . " +1 month");
echo $date . " ";

$date = strtotime(date("Y-m-d", strtotime($currentDate)) . " +30 days");

echo $date . " ";
?>

which displays the output as:

Current Date: 2011-10-29
1319950800
1320469200
1321077600
1322546400
1322460000

How can I get it to display the other dates as actual dates rather than what appear to be time stamps?

djon2003

Here is the code I use to add one hour.

$fileDate = new DateTime(date("Y/m/d H:i"));
$fileDate->modify("+1 hour");

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PeterErhard

ASKER

Thanks, but no good in just doing a copy/paste of what you posted:

Catchable fatal error: Object of class DateTime could not be converted to string in /home/..... on line 26

$fileDate = new DateTime(date("Y/m/d H:i"));
$fileDate->modify("+1 hour");

echo $fileDate;

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djon2003

This is a PHP object.

You shall use

$fileDate->format('Y/m/d');

djon2003

Well..

echo $fileDate->format('Y/m/d');

PeterErhard

ASKER

Thanks, still having trouble though as I want to add days and not hours:

$fileDate = new Date("Y-m-d");
$fileDate->modify("+7 days");

echo $fileDate->format('Y-m-d');

Fatal error: Class 'Date' not found in /home/cricketw/public_html/football/datetest.php on line 25

djon2003

Try to remove the "s" from days"

$fileDate = new Date("Y-m-d");
$fileDate->modify("+7 day");

echo $fileDate->format('Y-m-d');

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Keith Brown

strtotime by default uses UNIX time format, so need to format it.

<?php
$currentDate = date("Y-m-d");// current date
echo "Current Date: ".$currentDate."<br>";

//Add one Date
$date = date("Y-m-d, strtotime(date("Y-m-d", strtotime($currentDate)) . " +1 day"));
echo $date . "<br>";

$date = date("Y-m-d", strtotime(date("Y-m-d", strtotime($currentDate)) . " +1 week"));
echo $date . "<br>";  
$date = date("Y-m-d", strtotime(date("Y-m-d", strtotime($currentDate)) . " +2 week"));
echo $date . "<br>";  
$date = date("Y-m-d", strtotime(date("Y-m-d", strtotime($currentDate)) . " +1 month"));
echo $date . "<br>";  
$date = date("Y-m-d", strtotime(date("Y-m-d", strtotime($currentDate)) . " +30 days"));
echo $date . "<br>";
?>

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That's what you would need to do with existing code, however, it is a bit overblown. That code isn't very efficient. No need to use the $currentDate variable, because PHP defaults to using that anyway if you don't specify. So why add the time, convert that to a date, spit that string to be converted to a time, only to be processed back as a date?

<?php
$currentDate = date("Y-m-d");// current date
echo "Current Date: ".$currentDate."<br>";
//Add one Date
$date = date("Y-m-d", strtotime("+1 day"));
echo $date . "<br>";
$date = date("Y-m-d", strtotime("+1 week"));
echo $date . "<br>";
$date = date("Y-m-d", strtotime("+2 week"));
echo $date . "<br>";  
$date = date("Y-m-d", strtotime("+1 month"));
echo $date . "<br>";  
$date = date("Y-m-d", strtotime("+30 days"));
echo $date . "<br>";

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We can stream line that even more, by just doing away with the variables entirely.

<?php
echo "Current Date: " . date("Y-m-d") . "<br />"; //Current Date
echo date("Y-m-d", strtotime("+1 day")) . "<br />"; //Tomorrow
echo date("Y-m-d", strtotime("+1 week")) . "<br />"; //7 Days from now
echo date("Y-m-d", strtotime("+2 week")) . "<br />"; //14 Days from now
echo date("Y-m-d", strtotime("+1 month")) . "<br />"; //30 Days from now
echo date("Y-m-d", strtotime("+30 days")) . "<br />"; //Also 30 days from now
?>

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PeterErhard

ASKER

Thanks Hellmark, that gives me some good basis to work from.

I've got what I need working now with the below, but it does seem overly complex and messy.

$CompetitionStartDate = $_POST["YearStart"] . "-" . $_POST["MonthStart"] . "-" . $_POST["DayStart"];

$End = date('Y-m-d',strtotime(date("Y-m-d", strtotime($CompetitionStartDate)) . " +7 day"));

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ASKER CERTIFIED SOLUTION

Keith Brown

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PeterErhard

ASKER

Thanks HellMark, that does the trick perfectly and exactly what I was after.

Thanks so much. All looks a lot more simple now.