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find length of file depend on end marker

Posted on 2011-10-31
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Last Modified: 2012-05-12
Hi

after i run this command to search about end marker of jpeg file:

xxd image.raw | grep -i "ffd9" | head -n 7 ===>

0082560 2903 9068 ffd9 4bb1 f6d2 c69c 1a4c 7195      (..h[.K......nq

how i can calculate length of jpeg file include footer depend on output ?




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Question by:ang3lus
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by:raysonlee
ID: 37055316
Search for FFD8 which is the start of image and FFD9 which is the end of image, you'll then get the image size. Refer to detail JPG format here http://en.wikipedia.org/wiki/JPEG for more information.
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by:ang3lus
ID: 37055458

there is no possible to find length of file depend only on output.

cause the
the solution of above question is from output :

ffd9 end at 0082565 and the length of file is 0082566.

=================
I am not understand how 0082565 has been calculated and how length become 0082566( 0082565 +1)

thanks
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raysonlee earned 1000 total points
ID: 37055494
As the dump starts from byte 0 of the file, as shown in the output 29 is the 82560'th byte, d9 is the 82565'th byte, adding byte 0 will get the total file length of 82566.
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Author Closing Comment

by:ang3lus
ID: 37055563
many Thanks

you are helping me alot
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