string manipulation in Mssql 2008

Hi ,

I have a parameter list:
like  -LGENG -OF2 ORIENTL "VP1" "PS_PO_NCAAT0000020899_2464788".

I would like to replace the string completely beginning from VP1.  I believe I begin with the Left function.  What other functions would I need for the substitute with my new phrase.

Thanks,
Nigluc
BrockAsked:
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Partha MandayamTechnical DirectorCommented:
declare @str varchar(2000)
set @str='-LGENG -OF2 ORIENTL "VP1" "PS_PO_NCAAT0000020899_2464788"'

select left(@str, charindex('V',@str)-1) -- will give the desired result
--charindex finds the position of 'V' and we take all characters to the left of V and omit the rest

I think that's what you want.
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BrockAuthor Commented:
I tried this :

SELECT STUFF(PARMLIST,(CHARINDEX('ORIENTL',PARMLIST)+LEN('ORIENTL')),254,'"VP1" "TESTLNS"') FROM PSPRCSPARMS WHERE PRCSINSTANCE = '234031'

I will substitute the vp1, and testlns with variables.

Thank you,
nigluc
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BrockAuthor Commented:
Thanks,

I put my brain to work as it is on a deadline :-)
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