File Grep in unix

Here is a sample....

find / -type d '!' -exec test -f '{}/.qmail' ';' -print

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where

find - is find command in unix
/ - is the path to search in
-type d - search for directories only
'!' - negate the output of -exec command
-exec - execute sub command
test -f '{}/.qmail' - where it will test for existence of .qmail filename... replace with your desired filename
-print - prints matching list

Hope this helps!

Regards,

instead of printing the matching list can we do the non-matching list and I just want to find no need to replace anything.

pritamdutt's code works just fine

Can be put into a script like this:

if [ $# != 2 ]
then
	echo "$0 <dir> <file>"
else
	find $1 -type d '!' -exec test -f "{}/$2" ';' -print
fi

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make the script above executable and call like this:

./script basedir file