How to execute command+parameters in a Linux C Shell script

I would like to incorporate the following in my C Shell script.
packager --input-file=G:\Testing\test.txt --output-path=G:\Testing\out.txt duration=4

“Packager” is an executable command from a third party program. –input  and –output are parameters that can be passed to “Packager”

How do I execute the command and parameters  form a C Shell script?
What’s the correct syntax ?

Please bear in mind that this is just a part of a bigger C Shell script
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The statement is nearly correct.
Just escape the backslashes with a second one or put single quotes around the parameters ('--input-file...'
wademiAuthor Commented:
But how does c chell know that packager is an actual command
The shell will search for it in your PATH if it's not a shell builtin or a shell syntax element (which it isn't).

To be really sure you could add the full path (/path/to/packager)
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wademiAuthor Commented:
so just enter the command as is in my C Shell script?


path/packager `--input-file=G:\Testing\test.tx`t `--output-path=G:\Testing\out.tx`t `duration=4`
By the way - Linux does not use Windows-style paths as in your Q.
Where did you get them from?
wademiAuthor Commented:
I know the path is different. I have to do this project in both linux and windows. was the above sytax correct using / slash
An absolute path starts with a slash.

/path/packager '--input-file=G:\Testing\test.txt' '--output-path=G:\Testing\out.txt' 'duration=4'

Please use just single quotation marks ( 'apostrophe' ) not accents or the like.

Or do it this way:

/path/packager --input-file=G:\\Testing\\test.txt  --output-path=G:\\Testing\\out.txt  duration=4

Note: No quotes, but double backslashes.

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Unix OS

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