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# Using only non negative numbers

Hi guys: Can any one please explain this question? Thanks

How many solutions (using only non-negative integers) are there to the following equation ?

x1+x2+x3+x4+x5+x6+x7=20

Ans: C(26,6)=230,230

How many solutions (using only non-negative integers) are there to the following equation ?

x1+x2+x3+x4+x5+x6+x7=20

Ans: C(26,6)=230,230

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Thanks ozo. Can you please tell me why there is 7 rows group and then its going to 6 rows group

*ways to arrange 20 x's and 6 + signs in a row*

That shows a good understanding of math. I'm no math expert, so it took some thought to see how it applied. But it's an excellent restatement of the problem. Nice.

Tom

> why there is 7 rows group and then its going to 6 rows group

I'm not sure what you mean. there are always 7 groups of x's separated by +'s

(some of the groups may contain 0 x's, as long as the number of x's is a non-negative integer)

I'm not sure what you mean. there are always 7 groups of x's separated by +'s

(some of the groups may contain 0 x's, as long as the number of x's is a non-negative integer)

> why there is 7 rows group and then its going to 6 rows group

I think I understand what you mean now.

There are 7 examples of "If any one of them = 20, then all the rest are 0" and 6 examples of "If A = 19, then one of them = 1 and the rest are 0."

I think I understand what you mean now.

There are 7 examples of "If any one of them = 20, then all the rest are 0" and 6 examples of "If A = 19, then one of them = 1 and the rest are 0."

ASKER

ok thanks ozo.

each of which will produce a different solution to the equation