mustish1
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Using only non negative numbers
Hi guys: Can any one please explain this question? Thanks
How many solutions (using only non-negative integers) are there to the following equation ?
x1+x2+x3+x4+x5+x6+x7=20
Ans: C(26,6)=230,230
How many solutions (using only non-negative integers) are there to the following equation ?
x1+x2+x3+x4+x5+x6+x7=20
Ans: C(26,6)=230,230
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ASKER
Thanks ozo. Can you please tell me why there is 7 rows group and then its going to 6 rows group
ways to arrange 20 x's and 6 + signs in a row
That shows a good understanding of math. I'm no math expert, so it took some thought to see how it applied. But it's an excellent restatement of the problem. Nice.
Tom
That shows a good understanding of math. I'm no math expert, so it took some thought to see how it applied. But it's an excellent restatement of the problem. Nice.
Tom
> why there is 7 rows group and then its going to 6 rows group
I'm not sure what you mean. there are always 7 groups of x's separated by +'s
(some of the groups may contain 0 x's, as long as the number of x's is a non-negative integer)
I'm not sure what you mean. there are always 7 groups of x's separated by +'s
(some of the groups may contain 0 x's, as long as the number of x's is a non-negative integer)
> why there is 7 rows group and then its going to 6 rows group
I think I understand what you mean now.
There are 7 examples of "If any one of them = 20, then all the rest are 0" and 6 examples of "If A = 19, then one of them = 1 and the rest are 0."
I think I understand what you mean now.
There are 7 examples of "If any one of them = 20, then all the rest are 0" and 6 examples of "If A = 19, then one of them = 1 and the rest are 0."
ASKER
ok thanks ozo.
each of which will produce a different solution to the equation