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There are C(26,6) ways to arrange 20 x's and 6 + signs in a row<br />
each of which will produce a different solution to the equation
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There are C(26,6) ways to arrange 20 x's and 6 + signs in a row
each of which will produce a different solution to the equation

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Thanks ozo. Can you please tell me why there is 7 rows group and then its going to 6 rows group
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Thanks ozo. Can you please tell me why there is 7 rows group and then its going to 6 rows group

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<i>ways to arrange 20 x's and 6 + signs in a row</i><br />
<br />
That shows a good understanding of math. I'm no math expert, so it took some thought to see how it applied. But it's an excellent restatement of the problem. Nice.<br />
<br />
Tom<br />

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ways to arrange 20 x's and 6 + signs in a row

That shows a good understanding of math. I'm no math expert, so it took some thought to see how it applied. But it's an excellent restatement of the problem. Nice.

Tom


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&gt; why there is 7 rows group and then its going to 6 rows group<br />
I'm not sure what you mean. &nbsp;there are always 7 groups of x's separated by +'s<br />
(some of the groups may contain 0 x's, as long as the number of x's is a non-negative integer)
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> why there is 7 rows group and then its going to 6 rows group
I'm not sure what you mean.  there are always 7 groups of x's separated by +'s
(some of the groups may contain 0 x's, as long as the number of x's is a non-negative integer)

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&gt; why there is 7 rows group and then its going to 6 rows group<br />
I think I understand what you mean now.<br />
There are 7 examples of &quot;If any one of them = 20, then all the rest are 0&quot; and 6 examples of &quot;If A = 19, then one of them = 1 and the rest are 0.&quot;
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> why there is 7 rows group and then its going to 6 rows group
I think I understand what you mean now.
There are 7 examples of "If any one of them = 20, then all the rest are 0" and 6 examples of "If A = 19, then one of them = 1 and the rest are 0."

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Hi guys: Can any one please explain this question? Thanks<br />
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How many solutions (using only non-negative integers) are there to the following equation ?<br />
x1+x2+x3+x4+x5+x6+x7=20<br />
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Ans: C(26,6)=230,230<br />

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Hi guys: Can any one please explain this question? Thanks

How many solutions (using only non-negative integers) are there to the following equation ?
x1+x2+x3+x4+x5+x6+x7=20

Ans: C(26,6)=230,230


Using only non negative numbers

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