asked on

PHP or Javascript

I have 2 buttons on a page. Each calls the same resulting page, but I want to pass a hidden field filled with a different variable for each button.

My PHP code is very simple. Shown is one of the 2 buttons. But in checking the posted values on the subsequent page, it is blank.

What am I doing wrong?

<form id='account-form' action='abc.php' method='POST'>
<INPUT type='hidden' name='rcptdate'>

<?php
$DonateDt="20111107";
echo "<input class='pill-button' type='submit' value='Receipt' onClick='this.account-form.rcptdate.value=".$DonateDt."'; />";
?>

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COBOLdinosaur

change:

this.account-form.rcptdate.value

to this.value

Cd&

COBOLdinosaur

Sorry I miss read it

change it to forms.account-form.rcptdate.value

Cd&

kkbenj

ASKER

Changing this.account-form.rcptdate.value to forms.account-form.rcptdate.value did not work.

Just to be clear, I need to be able to set the value of the hidden field on click. The php code takes care of filling the variable $DonateDt, then upon click it needs to assign it.

Ray Paseur

You can use var_dump($_POST) to see the contents of the post array.

If you have two submit buttons, why no just detect which button was submitted by testing the value of the named submit button? Easy!

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COBOLdinosaur

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kkbenj

ASKER

Cobol - perfect and easy solution. Thanks for the speedy responses.

COBOLdinosaur

It would have been better if I had been paying better attention and got it right the first time. Need more coffee I think. :^)

Cd&