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I tried that, didn't work. Then removed the &gt;&nbsp;sign, now it works. Should that really be needed?
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I tried that, didn't work. Then removed the > sign, now it works. Should that really be needed?

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<div class="content wysiwyg-content">
Given the attached HTML, lets say I have a variable such as:<br />
<br />
var replaceImage='art/gr_numbe<wbr />r_1.jpg';<br />
<br />
How can I select the image based on its container ID (the DIV) and its 'src' attribute? I tried these two things with no luck:<br />
<br />
$('img[src$=removeImage]')<wbr />.fadeOut(2<wbr />00);<br />
$('src', removeImage).fadeOut(200);<wbr /><br />
<br />
Thanks!<br />

<pre><code id="code-8238673">&lt;div id=&quot;question1&quot;&gt;
&lt;img class=&quot;ranknum&quot; src=&quot;art/gr_number_1.jpg&quot; width=&quot;200&quot; height=&quot;240&quot; border=&quot;0&quot; /&gt;
&lt;/div&gt;</code></pre>
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Given the attached HTML, lets say I have a variable such as:

var replaceImage='art/gr_number_1.jpg';

How can I select the image based on its container ID (the DIV) and its 'src' attribute? I tried these two things with no luck:

$('img[src$=removeImage]').fadeOut(200);
$('src', removeImage).fadeOut(200);

Thanks!

jQuery: how to select and fadeOut an image based on container ID and 'src' attribute

jQuery (Core) is a cross-browser JavaScript library that provides abstractions for common client-side tasks such as Document Object Model (DOM) traversal, DOM manipulation, event handling, animation and Ajax. jQuery also provides a platform to create plugins that extend jQuery's capabilities beyond those already provided by the library.

jQuery

JavaScript is a dynamic, object-based language commonly used for client-side scripting in web browsers. Recently, server side JavaScript frameworks have also emerged. JavaScript runs on nearly every operating system and  in almost every mainstream web browser.