Complicated Duplicate Records MySQL Query

I have a table that I know has duplicate records.  The columns are named:STREET_NUMBER, STREET_NAME, STREET_TYPE, STREET_DIRECTION, UNIT_NUMBER

There is also a column called MLS_ID that makes this query difficult.

What is the proper SQL syntax to compare the address columns and display records where the MLS_ID do NOT match but the other columns DO match.

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SELECT a.* FROM table_name AS a, table_name AS b WHERE a.street_number = b.street_number AND a.mls_id!=b.mls_id //you can add as many conditions here

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nemws1Database AdministratorCommented:
PranjalShah has posted a query that most people would - however, it doesn't work correctly.  If you have 3 duplicated entries,  it will appear *6* times in this query (since for each of the MLS_ID values will not equal *two* of the other MLS_ID values).  It's exponential - the more duplicated the rows, the much more you'll see those records appear.

The best method (although I personally dislike sub-queries) is to use IN with a sub-select:
FROM table_name
  FROM table_name

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This example *excludes* the latest duplicate entry (change MAX to MIN to keep the earliest entry), so the IDS returned from it can be immediately deleted from the table.  However, for tables with many rows, it can be inefficient and slow.

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