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I think you need another category in there, assuming that 180 column shows dates between 180 and 365 then I think you need another column to show between 0 and 30 (marked as 0 on attached)....I'm assuming &quot;expired&quot; is any date in the past?<br />
<br />
Sample formula for between 180 and 365<br />
<br />
=IF(AND(B4-TODAY()&lt;365,B4-<wbr />TODAY()&gt;=1<wbr />80),&quot;X&quot;,&quot;&quot;<wbr />)<br />
<br />
regards, barry<br />
<a href="https://filedb.experts-exchange.com/incoming/2011/12_w50/530009/Licensing-barry.xlsx" target="_blank" class="file-inline" title="IF/AND (15 KB)"><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 512 512"><path d="M67.508 468.467c-58.005-58.013-58.016-151.92 0-209.943l225.011-225.04c44.643-44.645 117.279-44.645 161.92 0 44.743 44.749 44.753 117.186 0 161.944l-189.465 189.49c-31.41 31.413-82.518 31.412-113.926.001-31.479-31.482-31.49-82.453 0-113.944L311.51 110.491c4.687-4.687 12.286-4.687 16.972 0l16.967 16.971c4.685 4.686 4.685 12.283 0 16.969L184.983 304.917c-12.724 12.724-12.73 33.328 0 46.058 12.696 12.697 33.356 12.699 46.054-.001l189.465-189.489c25.987-25.989 25.994-68.06.001-94.056-25.931-25.934-68.119-25.932-94.049 0l-225.01 225.039c-39.249 39.252-39.258 102.795-.001 142.057 39.285 39.29 102.885 39.287 142.162-.028A739446.174 739446.174 0 0 1 439.497 238.49c4.686-4.687 12.282-4.684 16.969.004l16.967 16.971c4.685 4.686 4.689 12.279.004 16.965a755654.128 755654.128 0 0 0-195.881 195.996c-58.034 58.092-152.004 58.093-210.048.041z"/></svg>Licensing-barry.xlsx</a>
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I think you need another category in there, assuming that 180 column shows dates between 180 and 365 then I think you need another column to show between 0 and 30 (marked as 0 on attached)....I'm assuming "expired" is any date in the past?

Sample formula for between 180 and 365

=IF(AND(B4-TODAY()<365,B4-TODAY()>=180),"X","")

regards, barry
Licensing-barry.xlsx [https://filedb.experts-exchange.com/incoming/2011/12_w50/530009/Licensing-barry.xlsx]

Licensing-barry.xlsx

modification of bh's spreadsheet solution

Licensing-barry-mod.xlsx

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i would like to have an X displayed in whatever column the expiration date listed in column B is versus todays date for each activity listed in column A.<br />
<br />
The number in line 3 represent the days remaining before expiration of the license in the case of Auto registrations I filled in how I would like the sheet to work by plaing an X in the 365+ days reamining before license expiration.<br />
<br />
If posible please give me a formula based solution and not a macro.<br />
<br />
Thanks<br />
<a href="https://filedb.experts-exchange.com/incoming/2011/12_w50/530007/Licensing.xlsx" target="_blank" class="file-inline" title="sheet (10 KB)"><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 512 512"><path d="M67.508 468.467c-58.005-58.013-58.016-151.92 0-209.943l225.011-225.04c44.643-44.645 117.279-44.645 161.92 0 44.743 44.749 44.753 117.186 0 161.944l-189.465 189.49c-31.41 31.413-82.518 31.412-113.926.001-31.479-31.482-31.49-82.453 0-113.944L311.51 110.491c4.687-4.687 12.286-4.687 16.972 0l16.967 16.971c4.685 4.686 4.685 12.283 0 16.969L184.983 304.917c-12.724 12.724-12.73 33.328 0 46.058 12.696 12.697 33.356 12.699 46.054-.001l189.465-189.489c25.987-25.989 25.994-68.06.001-94.056-25.931-25.934-68.119-25.932-94.049 0l-225.01 225.039c-39.249 39.252-39.258 102.795-.001 142.057 39.285 39.29 102.885 39.287 142.162-.028A739446.174 739446.174 0 0 1 439.497 238.49c4.686-4.687 12.282-4.684 16.969.004l16.967 16.971c4.685 4.686 4.689 12.279.004 16.965a755654.128 755654.128 0 0 0-195.881 195.996c-58.034 58.092-152.004 58.093-210.048.041z"/></svg>Licensing.xlsx</a>
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Licensing.xlsx

i would like to have an X displayed in whatever column the expiration date listed in column B is versus todays date for each activity listed in column A.

The number in line 3 represent the days remaining before expiration of the license in the case of Auto registrations I filled in how I would like the sheet to work by plaing an X in the 365+ days reamining before license expiration.

If posible please give me a formula based solution and not a macro.

Thanks

Column population based on date

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