Java Static Binding?

Why does this Java code print out "Number" instead of "Double":
Is this to do with static binding?

public class TypesTest {

   public void print(Double d) {
      System.out.println("Double");
   }

   public void print(Number n) {
      System.out.println("Number");
   }

   public static void main(String[] args) {
      Number n = new Double(5);
      TypesTest t = new TypesTest();
      t.print(n);
   }
}
pipebeachAsked:
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for_yanCommented:
That is expected - this is methoid overloding. You are feeding parameter of tyope Number because n is declared as Number so it finds methoid whichexactly feeds the argument type. And that method would be print(Number) as n is Number.
This should not be mixed up ith polymorphism. If you would invoke method on the istance of n itself, like n.toString() then java would use the method of Double because n was created as Double(). But this is quite differentt case. When it is aboit methiod overloading then JVM just compares the tyupes of argument declared in the method signature not going into details of how those instances were created.
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for_yanCommented:
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