XSLT - Replacing last occurance of a character in a string

Maybe this will do

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:xs="http://www.w3.org/2001/XMLSchema"
    exclude-result-prefixes="xs"
    version="2.0">
    <xsl:variable name="str" select="'01-01-01-01h abc def'" />
        
    <xsl:template match="/">
        <xsl:value-of select="concat(string-join(tokenize($str, '-')[position() &lt; last()], '-'), ' ', tokenize($str, '-')[position() = last()])"></xsl:value-of>
    </xsl:template>
</xsl:stylesheet>

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wow...thats fairly complicated

Would it be easier if last '-' was alway followed by 2 numerics and then a character ? ie. -01h

It is not that complex.

I break the string in pieces at the '-'
I bring them all together except the last
I add the space
I add the last from the breakup

pretty convinced that this is the best performing solution
if you don't like the code, stuff it away in a function like this

You could do this with a regular expression if you were certain that -\d\dh would only occur once
see code in next comment

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:xs="http://www.w3.org/2001/XMLSchema"
    xmlns:pfn="#internal"
    exclude-result-prefixes="xs"
    version="2.0">
    <xsl:variable name="str" select="'01-01-01-01h abc def'" />
        
    <xsl:template match="/">
        <xsl:value-of select="pfn:replace-last-occurence-of($str, '-', ' ')"/>
    </xsl:template>
    
    <xsl:function name="pfn:replace-last-occurence-of">
        <xsl:param name="str"/>
        <xsl:param name="find"/>
        <xsl:param name="replace"/>
        <xsl:value-of select="concat(string-join(tokenize($str, $find)[position() &lt; last()], $find), $replace, tokenize($str, $find)[position() = last()])"></xsl:value-of>
    </xsl:function>
</xsl:stylesheet>

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