bash script

Hi,

 My script does not see to work properly, I would appreciate your input in order to make it work. Thanks in advance.

#!/bin/bash

LBPR1="http://loadbalancer/jkstatus"

[[ $1 = "" ]] && echo "The correct syntax is ./lbctl servername"
[[ $1 = "" ]] && exit
svr=$1


#Find out where the server is located
data=`wget -q ${LBPR1} -O - | grep $svr | awk -F"lb_node" '{print $2}' | awk -F"\"" '{print $1}' | wc -l`
dat2=`wget -q "${LBPR1}?cmd=edit&from=list&w=lbstore_lb&att=wa" -O - |  tr '\n' ' ' | sed 's/lb_node/\n&/g'| grep "lb_node${data}<"| awk -F"input name=" '{print $2}' | awk '{print $1}' | sed 's/\"//g'`
if [ ${data} -gt 1 ];then
       clear
       echo -n "Please enter 0 to take server out of the loop"
       echo -n "Please enter 1 to put server back in the loop"
               if [ $1 -eq 0 ] ; then
                        curl --silent POST "${LBPR1}/jkstatus?cmd=update&from=list&w=bfstore_lb&att=wa&re=10&val${dat2}=2"
               else
                        curl --silent POST "${LBPR1}/jkstatus?cmd=update&from=list&w=bfstore_lb&att=wa&re=10&val${dat2}=0"
                       
               fi
fi


[[ $data = "" ]] && {
echo "sorry, $svr does not look like it is part of a jk group"
exit
}

echo "$svr $dat2"

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dpoper1Asked:
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xtermCommented:
Can you be more specific about which part of it is failing and how?
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dpoper1Author Commented:
ok, here is my issue,

The purpose of this script is for me to enter the script with the servername:

 ./myscript servername

Then it will go out to multiple load balancers, and where it finds it; the script should prompt the user to take the server in and/or out of the loop. That portion is where the script is failing, it reads throughout the script and it does not prompt me for the action to perform, take a server in/out of the loop.


I would appreciate your input.

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xtermCommented:
 data=`wget -q ${LBPR1} -O - | grep $svr | awk -F"lb_node" '{print $2}' | awk -F"\"" '{print $1}' | wc -l`

This should be:

  data=`wget -q ${LBPR1} -O - | grep $1 | awk -F"lb_node" '{print $2}' | awk -F"\"" '{print $1}' | wc -l`

You're grepping for $svr, but there's no such variable, so it will always be null, and always return 0 after piping through wc -l.

Then of course, it will never enter your loop at line 13.
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dpoper1Author Commented:
Thank you, that worked, now, I have a quick question, out of the output below, how would you get the actual number of the myservers_node20, I would only need to extract the number "20" out of the entire 1 liner.

I would appreciate your input.
<td>[<a href="/jkstatus?cmd=edit&amp;from=list&amp;w=bfstore_lb&amp;sw=myservers_node20">E</a>|<a href="/jkstatus?cmd=reset&amp;from=list&amp;w=bfstore_lb&amp;sw=myservers_node20">R</a>]&nbsp;</td><td>myservers_node20</td><td>ajp13</td><td>vmapp220:11009</td><td>192.168.30.178:11009</td><td>ACT</td><td>OK</td><td>0</td><td>2</td><td>3</td><td>109</td><td>18809</td><td>0</td><td>101</td><td>0</td><td> 46M</td><td>2.7G</td><td>3</td><td>9</td><td>myservers_node20</td><td>&nbsp;</td><td>group16</td><td>0/0</td></tr>

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xtermCommented:
Are you talking about finding the string "myservers_node20" and then pulling the 20 out of that?
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dpoper1Author Commented:
Yes, I just need to pull out the numbers out could be a single double or triple
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xtermCommented:
It's a bit ugly, but this should do what you need regardless of how many digits are in the output:
yournum=`echo $data | sed s,"</td>","\n",g | head -2| tail -1 | tr [a-z] "\n" | tail -1`

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dpoper1Author Commented:
Thank you for your assistance, that helped.
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