php array

hi

how can i search the string of a key in a array?

for example if i had $test = array(':colour'=>'red', ':name'=>'john', 'age'=>13);

how could i search the key of each value and check if it begins with a colon?

thanks
MK15Asked:
Who is Participating?

[Product update] Infrastructure Analysis Tool is now available with Business Accounts.Learn More

x
I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

Greg AlexanderLead DeveloperCommented:
Here is a simple example of looping through it:

<?php
$test = array(':colour'=>'red', ':name'=>'john', 'age'=>13);

foreach($test as $k => $v){
	
	
	// now you have looped through each item, build in your search in your case a :
	if($k[0] == ':'){
		//here you would put all the matches into another array or echo them out
		echo "I have a colon ($k => $v)<br>";
		$colon_array[$k] = $v;
	}
}

// now show the colon items
echo "<pre>";
print_r($colon_array);
echo "</pre>";
?>

Open in new window

0

Experts Exchange Solution brought to you by

Your issues matter to us.

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Start your 7-day free trial
MK15Author Commented:
thank you, your help is appreciated:)
0
It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today
PHP

From novice to tech pro — start learning today.