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php regex function to get source location

JF0
JF0 asked
on
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Last Modified: 2012-05-12
Hi All,

Not too familiar with this but I think it should be simple for an expert with the subject.

The following  is an example of code stored in a variable on my site, I have many of these on the site that are just like this:

 
<img class="image10" title="" src="uploads/images/stock_photo_1.jpg" alt="" />

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I need a php function that will output only the data within the src quotes. Desired output for this example would be:

 
uploads/images/stock_photo_1.jpg

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Thank you in advance. 500pts for urgency.
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