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Regular expression in oracle

I need a regular expression in sql that truncates everything after the dash and including the dash.

For example:

I have 49858974-94984985
result 49858974

I have found some examples but not exactly what I need.
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meagain0707
Asked:
meagain0707
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2 Solutions
 
slightwv (䄆 Netminder) Commented:
Are all the numbers first?

select regexp_substr('49858974-94984985','[0-9]*') from dual;


If this doesn't work, please provide more samples.
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meagain0707Author Commented:
I think this will work. I will  let you know the results on Monday. Thank you.
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sujith80Commented:
If your string is not just numbers, use this

SQL> select regexp_substr('test-this', '[^-]+')
  2  from dual;

REGE
----
test

SQL>
SQL> select regexp_substr('49858974-94984985', '[^-]+')
  2  from dual;

REGEXP_S
--------
49858974

SQL>

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Guy Hengel [angelIII / a3]Billing EngineerCommented:
hmmm. do we really need regular expression? would a plain substr not be more efficient?
just curious:

select substr(yourfield, 0, instr(yourfield || '-', '-')-1) from yourtable 

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meagain0707Author Commented:
Thanks angelIII

The problem with the instr code you gave me is if the number starts  with -
then nothing is returned.
The reg. exp. still retuns the number after the -.
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slightwv (䄆 Netminder) Commented:
>>if the number starts  with -

This is a new requirement.  Do you have any other requirements that you have not mentioned?

Would you not want the '-' returned?

If so try:
regexp_substr('-49858974-94984985','-?[0-9]*')
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sujith80Commented:
have you tried my post

SQL> select regexp_substr('-49858974-94984985', '[^-]+') from dual;

REGEXP_S
--------
49858974

SQL> select regexp_substr('49858974-94984985', '[^-]+') from dual;

REGEXP_S
--------
49858974

SQL> select regexp_substr('49858974-', '[^-]+') from dual;

REGEXP_S
--------
49858974

SQL>

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