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Java - how to generate Random numbers in while loop

Posted on 2012-03-10
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431 Views
Last Modified: 2012-03-10
I want to generate two random numbers, then check for a condition, and as long as condition holds true, generate two new different random numbers.

This is what I have... and I suspect it's probably wrong...

Random hit = new Random();
				int rowRan = hit.nextInt(9);
				int colRan = hit.nextInt(9);
				
				while(ships[rowRan][colRan] == '-'  || ships[rowRan][colRan] == '*'){
					Random nexthit = new Random();
					rowRan = nexthit.nextInt(9);
					colRan = nexthit.nextInt(9);
				}
				rowInt = rowRan;
				colInt = colRan;

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Question by:Kyle Hamilton
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6 Comments
 
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Expert Comment

by:for_yan
ID: 37706076
you can do that, i believe, but you actually don't need to craete new Rndom every time:
Random hit = new Random();
				int rowRan = hit.nextInt(9);
				int colRan = hit.nextInt(9);
				
				while(ships[rowRan][colRan] == '-'  || ships[rowRan][colRan] == '*'){
					
					rowRan = hit.nextInt(9);
					colRan = hit.nextInt(9);
				}
				rowInt = rowRan;
				colInt = colRan;
                                  

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Expert Comment

by:for_yan
ID: 37706080
Random hit = new Random();

creates new random value using the cvurren millisecond as a seed,
after that each hit.nextInt(9) will generate a random int less than 9
you do not need to recreate the Random object every time - it will generate different random int less than 9 eech time ytou call it, so you don;t need ti recreate it every time
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Accepted Solution

by:
for_yan earned 500 total points
ID: 37706084
As it will be useing the current time as a seed every time and current time will be changing so, igf you would be creating the new Random every time it will have diofferent seed and will generate bew sequence, so probably it should not maytter in thuis case, but anyway you don't need to create new Random object every time
You create it once and then generate the random integers as much as you want
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Author Comment

by:Kyle Hamilton
ID: 37706085
I was hoping for that.

So when is a Random generated with the same "seed" giving you the same random number?

(not sure what I'm talking about... it's something I read..)
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Expert Comment

by:for_yan
ID: 37706088
yes,
if you say

Random r = new Random(25345123);

and then you say

int i = r.next(100);
let's assume each time you'll be getting as i say

41, 13, 12, 56...


then somehwre down the roda you again create the Random with the same seed


r = new Random(25345123);

and again do

i = r.nextInt(100);

several tiumes, then you'are guranteed that you'll be getting the same sequence:

41, 13, 12, 56...

That is waht mesans seed. If you use different seemd then sequence will be different

But within each sequence numbers are still coming in random way
So you don't need to create Random object again
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Author Closing Comment

by:Kyle Hamilton
ID: 37706089
cool. That's exactly what I wanted to know....

Thanks.
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