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Python TypeError

Posted on 2012-03-11
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Last Modified: 2012-03-12
Ok, so these lines usually work fine, but sometime produce type error (the bold part is producing it).
 1228         url = "http://www.google.com/" % params
 1229        [b] output = getPage("https://api-ssl.bitly.com/v3/shorten?login=xxx&apiKey=xxx&%s&format=txt"\
 1230         % urllib.urlencode({'longUrl':url}))[:22].replace("http://", "")[/b]

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Error:
TypeError: unsubscriptable object
      args = ('unsubscriptable object',)

Also in debug report, when this error occured both params and url variables were setup fine. HELP!
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Question by:GVNPublic123
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10 Comments
 
LVL 29

Expert Comment

by:pepr
ID: 37706777
You should copy/paste our error message with the trace.
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Author Comment

by:GVNPublic123
ID: 37706779
But I gave you traced line of code and error...what more do you need? There aint no more in report.
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LVL 29

Expert Comment

by:pepr
ID: 37707704
How do you run it?  Is it a part of some web server code?  Where the 'args = ...' came from?
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Author Comment

by:GVNPublic123
ID: 37707728
No idea...its just a random python fail.
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Author Comment

by:GVNPublic123
ID: 37707730
It occured, but I cant recreate it. I put exception handling for next time.
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LVL 29

Expert Comment

by:pepr
ID: 37707784
How do you run your Python code?  Is it saved in a file and launched say from command line?  How do you know that the mentioned line caused the error?  What version of Python do you use?  What OS do you use?
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Author Comment

by:GVNPublic123
ID: 37707813
CentOS 5, its a website, python 2.4.3

Got it from bug report.
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Accepted Solution

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pepr earned 2000 total points
ID: 37708614
OK.  I cannot help too much here.  If you know it was the line
1229  output = getpage(...)[:22].replace("http://", "")[/b]

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The error generally means that you try to index/slice what cannot be indexed -- i.e. the object you probably got cannot be sliced using the [:22].  It is likely that the getpage() returned None as the error result or something like that.

Try to avoid that kind of method chaining if the code is a bit complex and if it can fail:
    output = ''         # or some better initial value
    page = getpage(...)
    if page:              # or some more explicit testing
        output = page[:22].replace(...)

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Author Comment

by:GVNPublic123
ID: 37708635
Yeh, I put exception handling in so now I dont care if slicing fails. The worker will pick it up later automatically if it fails on request.
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Expert Comment

by:pepr
ID: 37708691
Sorry I could not be more explicit.  Thanks for the points, and have a good time ;)
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