xpath xml insert data duplicate nodes

how do you insert data from c# into an xml that was duplicate nodes?

Who is Participating?

[Product update] Infrastructure Analysis Tool is now available with Business Accounts.Learn More

I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

käµfm³d 👽Commented:
What do you mean by "duplicate nodes"? It's not clear from your example XML what you mean.
anarki_jimbelSenior DeveloperCommented:
Yes, please explain the task
goodluck11Author Commented:
the //name node is the same repeated on the document

if we are using

XmlElement name= (XmlElement)doc1.SelectSingleNode("//name");

and have multiple nodes with <name>, how do we access node#1, node #2, and so on,,
Python 3 Fundamentals

This course will teach participants about installing and configuring Python, syntax, importing, statements, types, strings, booleans, files, lists, tuples, comprehensions, functions, and classes.

käµfm³d 👽Commented:
If you use SelectNodes instead of SelectSingleNode, then you would have access to all name nodes within the document (because you are applying the XPath to the document itself and not any particular child node). The XPath you are using would not need to change; just the function you are calling.
anarki_jimbelSenior DeveloperCommented:
I wrote a simple code:
        private void button1_Click(object sender, EventArgs e)
         // read all book elements   
            XmlDocument doc = new XmlDocument();
            XmlNodeList bookdetails = doc.GetElementsByTagName("bookdetails");

            // For each book oget a name and print it; any other book elements can be accessed here
            foreach (XmlNode book in bookdetails)
                XmlNode nameNode = book.SelectSingleNode("./name"); // we suggest only one name element exists for a book
                System.Diagnostics.Debug.WriteLine("Name = " + nameNode.InnerText); // see output window

Open in new window

There are comments in the code, should be quitye clear.

I believe it is better to get book nodes ("bookdetails") and check any children like "name" elements, because books may have other elements like "author", ISBN", "publisher" etc.

Experts Exchange Solution brought to you by

Your issues matter to us.

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Start your 7-day free trial
käµfm³d 👽Commented:
I believe it is better to get book nodes ("bookdetails") and check any children like "name" elements, because books may have other elements like "author", ISBN", "publisher" etc.
If that's the case, then you can just alter the original XPath:

XmlNodeList names = doc1.SelectNodes("//bookdetails/name");

Open in new window

anarki_jimbelSenior DeveloperCommented:
kaufmed, I agree, if we do care about names only - this is a good approach.
But what if I want to print names along with authors and ISBNs etc.? Get three or more not really synchronised lists?

Yes, of course, in my code to get books we may use XPath instead a GetElementsByTagName method :)
It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today

From novice to tech pro — start learning today.