Improve company productivity with a Business Account.Sign Up

x
?
Solved

Java Network Programming

Posted on 2012-03-12
3
Medium Priority
?
259 Views
Last Modified: 2012-06-27
Would like to set up a network listener for a particular ip address so that when a connection is established to that particular destination certain programs can be executed....


Thanks In Advance....
0
Comment
Question by:CCBRONET
3 Comments
 
LVL 86

Expert Comment

by:CEHJ
ID: 37710262
Then you'll need some kind of proxy server. Services are provide via an address AND a port. You need to listen there and then forward to the real service
0
 
LVL 1

Expert Comment

by:RodSingh
ID: 37710468
import java.io.IOException;
import java.net.ServerSocket;
import java.net.Socket;

public class NetworkListener {

      private static int LISTENER_ADDRESS = 4446;
      public static void main(String[] args) {

            try {
                  ServerSocket serverSocket = new ServerSocket( LISTENER_ADDRESS);                  
                  while (true) {
                        System.out.println("The listener is ready to accept connection...");
                        Socket clientSocket = serverSocket.accept();
                        Thread thread = new Thread() {
                              public void run() {
                                    System.out.println("Execute your program");
                              }
                        };
                        thread.start();
                  }
            } catch (IOException e) {            
                  e.printStackTrace();
            }

      }
}
0
 
LVL 3

Accepted Solution

by:
jcgd earned 1500 total points
ID: 37715355
// to bind a specif ip address

            InetAddress addrIpName = InetAddress.getByName("172.30.1.18");
//      or
//      InetAddress addrName = InetAddress.getByName("myhost.name");
//    or
//            InetAddress addrIp = InetAddress.getByAddress(new byte[] { (byte)172,30,1,18});
            int port = 4446;
                int bl = 5;
            ServerSocket serverSocket = new ServerSocket(port,bl,addrIpName);
0

Featured Post

Get expert help—faster!

Need expert help—fast? Use the Help Bell for personalized assistance getting answers to your important questions.

Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.

Join & Write a Comment

This is the first one of a series of articles I’ll be writing to address technical issues that are always referred to as network problems. The network boundaries have changed, therefore having an understanding of how each piece in the network  puzzl…
In this post we will learn different types of Android Layout and some basics of an Android App.
Viewers will learn one way to get user input in Java. Introduce the Scanner object: Declare the variable that stores the user input: An example prompting the user for input: Methods you need to invoke in order to properly get  user input:
This video teaches viewers about errors in exception handling.

607 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question